ajax如何调用本页数据源不用一般处理程序

ajax如何调用本页数据源不用一般处理程序

摘自：http://www.cnblogs.com/LYunF/archive/2012/08/31/2665188.html

CS代码

View Code 
using System;
 using System.Data;
 using System.Configuration;
 using System.Collections;
 using System.Web;
 using System.Web.Security;
 using System.Web.UI;
 using System.Web.UI.WebControls;
 using System.Web.UI.WebControls.WebParts;
 using System.Web.UI.HtmlControls;
 using System.Web.Services;
 
 public partial class TestAjax : System.Web.UI.Page
 {
     protected void Page_Load(object sender, EventArgs e)
     {
         string methor = Request["act"];
         if (!string.IsNullOrEmpty(methor))
         {
             this.GetType().GetMethod(methor).Invoke(this, null);
         }
 
     }
 
     public void GetVal()
     {
         string val = "getVal 方法获取参数" + Request["arg"];
         Response.Clear();
         Response.Write(val);
         Response.End();
     }
 
 }

页面代码

View Code 
<%@ Page Language="C#" AutoEventWireup="true" CodeFile="TestAjax.aspx.cs" Inherits="TestAjax" %>
 
 <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
 
 <html xmlns="http://www.w3.org/1999/xhtml" >
 <head runat="server">
     <title>无标题页</title>
      <script type="text/javascript" src="Js/jquery-1.8.1.min.js" language="javascript"></script>
      <script language="javascript" type="text/javascript">
    
          function test()
          {
              
                  var data = new Object();
                 data.act = "GetVal";
                 data.arg = "123";
                 $.post("TestAjax.aspx", data, function (data) { alert(data); });
          }
      </script>
      
      
 </head>
 <body>
     <form id="form1" runat="server">
     <div>
         <input id="Button1" onclick="test()" type="button" value="测试ajax" />
 
     </div>
     </form>
 </body>
 </html>

 

 

posted @ 2012-08-31 13:57  only_copy  阅读(82)  评论(0)  编辑  收藏  举报