摘要: 1 var xhr = new XMLHttpRequest(); 2 xhr.open('GET', '文件地址.mp4'); 3 xhr.setRequestHeader("Content-type", "application/x-www-form-urlencoded"); 4 xhr.responseType = "blob"; 5 xhr.onprogress = function ( 阅读全文
posted @ 2019-09-20 15:24 oneall 阅读(8230) 评论(0) 推荐(0) 编辑