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摘要: 题目描述: 方法一:O(MN) O(M) class Solution: def isSubStructure(self, A: TreeNode, B: TreeNode) -> bool: def equal(A,B): if not B:return True if not A or A.va 阅读全文
posted @ 2020-04-17 15:11 oldby 阅读(91) 评论(0) 推荐(0) 编辑
摘要: 方法一:迭代 class Solution { public ListNode reverseList(ListNode head) { ListNode pre = null; ListNode cur = head; ListNode tmp = null; while(cur!=null){ 阅读全文
posted @ 2020-04-16 16:29 oldby 阅读(118) 评论(0) 推荐(0) 编辑
摘要: 题目描述: java:快慢指针: /** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; } * } */ 阅读全文
posted @ 2020-04-15 23:50 oldby 阅读(279) 评论(0) 推荐(0) 编辑
摘要: 题目描述: 方法一:dfs O(MN) O(MN) class Solution: def updateMatrix(self, matrix: List[List[int]]) -> List[List[int]]: m,n = len(matrix),len(matrix[0]) dist = 阅读全文
posted @ 2020-04-15 23:43 oldby 阅读(190) 评论(0) 推荐(0) 编辑
摘要: 方法一:栈 /** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; } * } */ class Solut 阅读全文
posted @ 2020-04-14 22:29 oldby 阅读(139) 评论(0) 推荐(0) 编辑
摘要: 题目描述: 方法一:逻辑判断法:O(N) class Solution: def isNumber(self, s: str) -> bool: s = s.strip() met_dot = met_e = met_digit = False for i, char in enumerate(s) 阅读全文
posted @ 2020-04-14 22:02 oldby 阅读(149) 评论(0) 推荐(0) 编辑
摘要: 题目描述: java: package test; import java.util.ArrayList; import java.util.HashMap; import java.util.HashSet; import java.util.List; import java.util.Map; 阅读全文
posted @ 2020-04-14 07:15 oldby 阅读(196) 评论(0) 推荐(0) 编辑
摘要: 题目描述: 方法: class Solution: def intersection(self, start1, end1, start2, end2): x1, y1, x2, y2, x3, y3, x4, y4 = *start1, *end1, *start2, *end2 det = la 阅读全文
posted @ 2020-04-13 10:10 oldby 阅读(112) 评论(0) 推荐(0) 编辑
摘要: 题目描述: 方法一: class Solution: def numOfWays(self, n: int) -> int: mod = int(1e9+7) s = ['ryr','ryg','rgr','rgy','yrg','ygr','ygy','yry','gry','grg','gyr' 阅读全文
posted @ 2020-04-12 20:09 oldby 阅读(289) 评论(0) 推荐(0) 编辑
摘要: 题目描述: 自己的提交: class Solution: def entityParser(self, text: str) -> str: text = text.replace(""","\"") text = text.replace("'","\'") text = te 阅读全文
posted @ 2020-04-12 19:46 oldby 阅读(153) 评论(0) 推荐(0) 编辑
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