摘要: 题目描述: 方法一:递归 class Solution: def mirrorTree(self, root: TreeNode) -> TreeNode: if not root:return root.left,root.right = self.mirrorTree(root.right),s 阅读全文
posted @ 2020-04-21 19:41 oldby 阅读(102) 评论(0) 推荐(0) 编辑
摘要: 题目描述: 方法:动态规划: class Solution: def numOfArrays(self, n: int, m: int, k: int) -> int: mod = 10 ** 9 + 7 dp = [[[0] * (k + 1) for _ in range(m + 1)] for 阅读全文
posted @ 2020-04-21 11:17 oldby 阅读(222) 评论(0) 推荐(0) 编辑