leetcode-1510-石子游戏Ⅳ

题目描述:

 

 

 

 

 方法:动态规划

class Solution:
    def winnerSquareGame(self, n: int) -> bool:
        dp = [False, True, False]
        for x in range(3, n+1):
            dp.append(False)
            for y in range(1, n):
                a = x - y * y
                if a < 0: break
                if not dp[a]:
                    dp[x] = True
                    break
        return dp[n]

 

posted @ 2020-07-13 23:23  oldby  阅读(139)  评论(0编辑  收藏  举报