leetcode-189周赛-1450-在既定时间做作业人数

 

 

 提交:

class Solution:
    def busyStudent(self, startTime: List[int], endTime: List[int], queryTime: int) -> int:
        count = 0
        for i in range(len(startTime)):
            if startTime[i] <= queryTime <= endTime[i]:
                count += 1
        return count

 另:

class Solution:
    def busyStudent(self, startTime: List[int], endTime: List[int], queryTime: int) -> int:
        return sum(a<=queryTime<=b for a,b in zip(startTime,endTime))

 

posted @ 2020-05-19 19:33  oldby  阅读(135)  评论(0编辑  收藏  举报