leetcode-1905-山脉数组中查找目标值

 

方法:二分查找

def binary_search(mountain, target, l, r, key=lambda x: x):
    target = key(target)
    while l <= r:
        mid = (l + r) // 2
        cur = key(mountain.get(mid))
        if cur == target:
            return mid
        elif cur < target:
            l = mid + 1
        else:
            r = mid - 1
    return -1

class Solution:
    def findInMountainArray(self, target: int, mountain_arr: 'MountainArray') -> int:
        l, r = 0, mountain_arr.length() - 1
        while l < r:
            mid = (l + r) // 2
            if mountain_arr.get(mid) < mountain_arr.get(mid + 1):
                l = mid + 1
            else:
                r = mid
        peak = l
        index = binary_search(mountain_arr, target, 0, peak)
        if index != -1:
            return index
        index = binary_search(mountain_arr, target, peak + 1, mountain_arr.length() - 1, lambda x: -x)
        return index

 

 

 

def binary_search(mountain, target, l, r, key=lambda x: x):
    target = key(target)
    while l <= r:
        mid = (l + r) // 2
        cur = key(mountain.get(mid))
        if cur == target:
            return mid
        elif cur < target:
            l = mid + 1
        else:
            r = mid - 1
    return -1

class Solution:
    def findInMountainArray(self, target: int, mountain_arr: 'MountainArray') -> int:
        l, r = 0, mountain_arr.length() - 1
        while l < r:
            mid = (l + r) // 2
            if mountain_arr.get(mid) < mountain_arr.get(mid + 1):
                l = mid + 1
            else:
                r = mid
        peak = l
        index = binary_search(mountain_arr, target, 0, peak)
        if index != -1:
            return index
        index = binary_search(mountain_arr, target, peak + 1, mountain_arr.length() - 1lambda x: -x)
        return index


posted @ 2020-04-30 09:01  oldby  阅读(163)  评论(0编辑  收藏  举报