leetcood学习笔记-21**-合并两个有序链表
题目描述:
方法一:
# Definition for singly-linked list. # class ListNode: # def __init__(self, x): # self.val = x # self.next = None class Solution: def mergeTwoLists(self, l1: ListNode, l2: ListNode) -> ListNode: res = ListNode(None) node = res while l1 and l2: if l1.val<l2.val: node.next,l1=l1,l1.next else: node.next,l2=l2,l2.next node = node.next if l1: node.next=l1 else: node.next=l2 return res.next
方法二:递归
class Solution: def mergeTwoLists(self, l1: ListNode, l2: ListNode) -> ListNode: if l1 is None and l2 is None: return None if l1 is None: return l2 if l2 is None: return l1 if l1.val > l2.val: l2.next = self.mergeTwoLists(l1, l2.next) return l2 l1.next = self.mergeTwoLists(l1.next, l2) return l1
python 数据结构之单链表的实现
链接:https://www.cnblogs.com/yupeng/p/3413763.html