846. Hand of Straights - LeetCode
Question
Solution
题目大意:打牌,判断牌是否能全部按顺子出
思路:构造一个list,存储1,2,3,4,5,6,7,8并排序,构造一个map存储每个数对应出现的次数
Java实现:
public boolean isNStraightHand(int[] hand, int W) {
List<Integer> nums = new ArrayList<>();
Map<Integer, Integer> map = new HashMap<>(); // num, count
for (int tmp : hand) {
Integer count = map.get(tmp);
if (count == null) {
count = 0;
nums.add(tmp);
}
map.put(tmp, count+1);
}
Collections.sort(nums); // sort
int i=0;
while (i < nums.size()) {
int tmp = nums.get(i);
int offset = 0;
while (offset < W) {
Integer count = map.get(tmp + offset);
if (count == null || count < 1) return false;
map.put(tmp + offset, count-1);
offset++;
}
while (i < nums.size() && map.get(nums.get(i)) == 0) i++;
}
return true;
}