Codeforces Round #320 (Div. 1) C. Weakness and Poorness
You are given a sequence of n integers a1, a2, ..., an.
Determine a real number x such that the weakness of the sequence a1 - x, a2 - x, ..., an - x is as small as possible.
The weakness of a sequence is defined as the maximum value of the poorness over all segments (contiguous subsequences) of a sequence.
The poorness of a segment is defined as the absolute value of sum of the elements of segment.
The first line contains one integer n (1 ≤ n ≤ 200 000), the length of a sequence.
The second line contains n integers a1, a2, ..., an (|ai| ≤ 10 000).
Output a real number denoting the minimum possible weakness of a1 - x, a2 - x, ..., an - x. Your answer will be considered correct if its relative or absolute error doesn't exceed 10 - 6.
3
1 2 3
1.000000000000000
4
1 2 3 4
2.000000000000000
10
1 10 2 9 3 8 4 7 5 6
4.500000000000000
For the first case, the optimal value of x is 2 so the sequence becomes - 1, 0, 1 and the max poorness occurs at the segment "-1" or segment "1". The poorness value (answer) equals to 1 in this case.
For the second sample the optimal value of x is 2.5 so the sequence becomes - 1.5, - 0.5, 0.5, 1.5 and the max poorness occurs on segment "-1.5 -0.5" or "0.5 1.5". The poorness value (answer) equals to 2 in this case.
三分+DP
不过 要注意精度
#include <iostream> #include<stdio.h> using namespace std; int a[300000],n; double _fabs(double val) { return (val>0?val:-val); } double check(double val) { double _max,sum; _max=0; sum=0; for(int i=1;i<=n;i++) { sum=(sum>0?sum:0)+a[i]-val; _max=max(_max,sum); } sum=0; for(int i=1;i<=n;i++) { sum=(sum<0?sum:0)+a[i]-val; _max=max(_max,-sum); } return _max; } int main() { double left,right,mid1,mid2; while(scanf("%d",&n)!=EOF) { for(int i=1;i<=n;i++) scanf("%d",&a[i]); left=-100000; right=100000; while(_fabs(left-right)>1e-11) { mid1=(2*left+right)/3.0; mid2=(left+2*right)/3.0; if (check(mid1)<check(mid2)) right=mid2; else left=mid1; } printf("%.12lf\n",check((left+right)/2.0)); } return 0; } /* 20 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 */