摘要：
/****点到直线的距离**** 过点（x1,y1）和点（x2,y2）的直线方程为：KX -Y + (x2y1 - x1y2)/(x2-x1) = 0* 设直线斜率为K = (y2-y1)/(x2-x1),C=(x2y1 - x1y2)/(x2-x1)* 点P(x0,y0)到直线AX + BY +C =0DE 距离为：d=|Ax0 + By0 + C|/sqrt(A*A + B*B)* 点（x3,y3）到经过点（x1,y1）和点（x2,y2）的直线的最短距离为：* distance = |K*x3 - y3 + C|/sqrt(K*K + 1)*/public static double Ge 阅读全文
摘要：
using System;using ESRI.ArcGIS.Carto;using ESRI.ArcGIS.Geometry;using ESRI.ArcGIS.Geodatabase;using ESRI.ArcGIS.NetworkAnalysis;namespace GisEditor{/// /// 最短路径分析/// public class ClsPathFinder{ private IGeometricNetwork m_ipGeometricNetwork; private IMap m_ipMap; private IPointCollection m_ipPoints; 阅读全文