1.29

 1 (define (sum term a next b)
 2   (if (> a b)
 3       0
 4       (+ (term a)
 5          (sum term (next a) next b))))
 6 
 7 (define (cube x)
 8   (* x x x))
 9 
10 
11 
12 (define (integral f a b n)
13   (define (helper f a b n k)
14     (define (next k)
15       (+ a (* k (/ (- b a) n))))
16     (cond ((= k n) (f (next k)))
17           ((= k 0) (+ (f (next k))
18                       (helper f a b n 1)))
19           ((= (remainder k 2) 0) (+ (* 2 (f (next k)))
20                                     (helper f a b n (+ k 1))))
21           (else (+ (* 4 (f (next k)))
22                    (helper f a b n (+ k 1))))))
23   (/ (* (helper f a b n 0) (/ (- b a) n)) 3))
24 
25 
26 
27 ----- 出现 xxxx is not applicable 的错误, 有可能是由于把函数写成了中缀表达式的情况.

 




1.30

1 (define (sum term a next b)
2   (define (iter a result)
3     (if (= a b)
4         result
5         (iter (next a) (+ result
6                           (term a)))))
7   (iter a 0))


1.31

---> 没必要写,和前面差不多


1.32

1 (define (accumulate combiner null-value term a next b)
2   (if (> a b)
3       null-value
4       (combiner (term a)
5                 (accumulate combiner null-value term (next a) next b))))



1.33

----> 类似 不写了就...

posted on 2016-05-01 13:14  内脏坏了  阅读(265)  评论(0编辑  收藏  举报