C++ Primer 读书笔记 - 第十四章

1. An overloaded operator must have at least one operand of class or enumeration type.

2. Default arguments for overloaded operators are illegal, except for operator(), the function-call operator.

3. The assignment (=), subscript ([]), call (()), and member access arrow (->) operators must be defined as members. Defining any of these operators as a nonmember function is flagged at compile time as an error.

    Like assignment, the compound-assignment operators ordinarily ought to be members of the class. Unlike assignment, they are not required to be so and the compiler will not complain if a nonmember compound-assignment operator is defined.

    Other operators that change he state of their object or that are closely tied to their given type - such as increment, decrement, and dereference - usually should be members of the class.

    Symmetric operators, such as the arithmetic, equality, relational, and bitwise operators, are best defined as ordinary nonmember functions.

4. < 和 == 的定义应该保持一致。

5. 定义下标操作的类,应该有两个版本:返回引用的非const成员,返回const引用的const成员。

6. 不用为ScreenPtr类定义默认构造函数,因此,一个ScreenPtr对象将总是指向一个Screen对象,不会有未绑定的ScreenPtr,这一点和内置指针不同。

6. Function Object

class GT_cls {
public:
    GT_cls(size_t val = 0) : bound(val) { }
    bool operator() (const string &s) { return s.size() >= bound; }
private:
    std::string::size_type bound;
};

count_if(words.begin(), words.end(), GT_cls(6));

count_if的原型是
template <class InputIterator, class UnaryPredicate>
  typename iterator_traits<InputIterator>::difference_type
    count (InputIterator first, InputIterator last, UnaryPredicate pred)
{
  typename iterator_traits<InputIterator>::difference_type ret = 0;
  while (first!=last) {
    if (pred(*first)) ++ret;
    ++first;
  }
  return ret;
}

由于类重载了()操作符,所以pred(*first)仍然可用。

 

 

 

posted on 2013-06-02 00:59  NULL00  阅读(686)  评论(0编辑  收藏  举报

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