Java 静态代码块执行顺序
public class Test1
{
public static int k=0;
public static Test1 t1 = new Test1("t1");
public static Test1 t2 = new Test1("t2");
public static int i = print("i");
public static int n = 99;
public static int j = print("j");
{
print("构造块");
}
static
{
print("静态块");
}
public Test1(String str)
{
System.out.println((++k)+":"+str+" i="+i+" n="+n);
++i;
++n;
}
public static int print(String str)
{
System.out.println((++k)+":"+str+" i="+i+" n="+n);
++n;
return ++i;
}
public static void main(String[] args)
{
Test1 t = new Test1("init");
}
}
输出
1:构造块 i=0 n=0
2:t1 i=1 n=1
3:构造块 i=2 n=2
4:t2 i=3 n=3
5:i i=4 n=4
6:j i=5 n=99
7:静态块 i=6 n=100
8:构造块 i=7 n=101
9:init i=8 n=102
posted on 2014-05-17 13:22 Sunny_NUAA 阅读(353) 评论(0) 编辑 收藏 举报