//4671914 2011-09-28 15:07:14 Accepted 1698 843MS 3260K 1905 B G++ nkhelloworld
//4671915 2011-09-28 15:07:18 Accepted 1698 453MS 3304K 1905 B C++ nkhelloworld
//线段树解决,近似序列求和问题,简单
/*
一个N<=100000个数组成的序列,最多做Q<=100000次操作,每一次操作由a,b,c组成,
意思是将[a,b]区间的值修改为c,求经过Q次操作后序列的总和
*/
#include <cstdio>
#define MAXN 100000
struct SEGMENTTREE
{
    int left,right,color;
}tree[MAXN*4+1];

void buildsegtree(int root,int l,int r)
{
    tree[root].left = l;    tree[root].right = r;   tree[root].color = 1;
    if(l != r)
    {
        int mid = (l+r)>>1;
        buildsegtree(root<<1,l,mid);
        buildsegtree(root<<1|1,mid+1,r);
    }
}

void update(int root,int a,int b,int c)
{
    if(tree[root].left == tree[root].right)
    {
        tree[root].color = c;
        return ;
    }
    if(tree[root].color != 0)
    {
        tree[root<<1].color = tree[root].color;
        tree[root<<1|1].color = tree[root].color;
        tree[root].color = 0;
    }
    if(a == tree[root].left && b == tree[root].right)
    {
        tree[root].color = c;
        return ;
    }
    int mid = (tree[root].left + tree[root].right) >>1;
    if( b <= mid )
        update(root<<1,a,b,c);
    else if(a > mid)
        update(root<<1|1,a,b,c);
    else
    {
        update(root<<1,a,mid,c);
        update(root<<1|1,mid+1,b,c);
    }
}

int query(int root,int left,int right)
{
    if(tree[root].color!=0)
        return (right - left + 1) * tree[root].color;
    int mid = (left + right) >> 1;
    if(right <= mid)
        return query(root<<1, left, right);
    else if(left > mid)
        return query(root<<1|1, left,right);
    else
        return query(root<<1, left, mid) + query(root<<1|1, mid+1,right);
}

int main()
{
    int totcase,numcase,i,n,q,a,b,c;
    scanf("%d",&totcase);
    for(numcase = 1;numcase <= totcase; numcase++)
    {
        scanf("%d%d",&n,&q);
        buildsegtree(1,1,n);
        for(i=1;i<=q;i++)
        {
            scanf("%d%d%d",&a,&b,&c);
            update(1,a,b,c);
        }
        printf("Case %d: The total value of the hook is %d.\n",numcase,query(1,1,n));
    }
    return 0;
}

posted on 2011-09-28 15:12  NKHe!!oWor!d  阅读(224)  评论(0编辑  收藏  举报