C#破解access数据库密码方法

C#破解access数据库密码方法

// 根据网上经验和方法用C#做一个破解程序
// 本程序最多取16位密码
using System.IO;
using System.Windows.Forms;
class Access
{
  // 获取密码
  static string GetPassword(string file)
  {                       // 未加密的文件0x42开始至0x61之前的每间隔一字节的数值
    byte[] baseByte = { 0xbe,0xec,0x65,0x9c,0xfe,0x28,0x2b,0x8a,0x6c,0x7b,0xcd,0xdf,0x4f,0x13,0xf7,0xb1, };
    byte flagByte   = 0x0c; // 标志 0x62 处的数值
    string password = "";
    try
    {
      FileStream fs = File.OpenRead(file);
      fs.Seek(0x14, SeekOrigin.Begin);
      byte ver = (byte)fs.ReadByte();     // 取得版本, 1为Access2000, 0为Access97
      fs.Seek(0x42, SeekOrigin.Begin);
      byte[] bs = new byte[33];
      if (fs.Read(bs, 0, 33) != 33) return "";
      byte flag = (byte)(bs[32] ^ flagByte);
      for(int i = 0; i < 16; i++)
      {
        byte b = (byte)(baseByte^bs[i*2]);
        if (i%2==0 && ver==1) b ^= flag;  //Access 2000
        if (b > 0) password += (char)b;
      }
    }
    catch {}
    return password;
  }
  // 主入口
  static void Main()
  {
    OpenFileDialog f = new OpenFileDialog();
    if (f.ShowDialog() != DialogResult.OK) return;
    MessageBox.Show("密码:[" + GetPassword(f.FileName) + "]", "密码");
  }
} 

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