深度优先算法之数组全排列问题

数组中任意n个数的全排列(DFS)以及任意n个数的组合

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

#define MAX 100
/*
求数组中任意n个数的全排列
 */
int result[MAX] = {0};
int count = 0;
int visited[MAX] = {0};

void dfs(int *a, int size, int num, int n)
{
    if (num == n) {
        for (int i = 0; i < count; i++) {
            printf("%d", result[i]);
        }
        printf("\n");
        return;
    }
    else {
        for (int i=0; i < size; i++) {
            if (visited[i] == 0) {
                result[count++] = a[i];
                visited[i] = 1;
                dfs(a, size, num+1, n);
                visited[i] = 0;
                count--;
            }
        }
    }

}

int main()
{
    int n;
    int a[10] = {0,1,2,3,4,5,6,7,8,9};
    scanf("%d", &n);
    dfs(a, 10,0, n);
    return 0;
}

代码比较简单,不做多余解释

posted @ 2020-11-19 13:59  牛牛码代码  阅读(129)  评论(0编辑  收藏  举报