在异步回调中调用MessageBox.Show

        public static void Test()
        {
            ThreadStart aThreadStart = delegate()
            {
                Thread.Sleep(1000);
                MessageBox.Show("Good!");
            };

            var aThread = new Thread(aThreadStart);
            aThread.Start();
        }

 

posted @ 2015-03-21 15:32  泪已凝  阅读(616)  评论(0编辑  收藏  举报