纸牌24点,Python 程序实现
最近刚刚接触 python,又恰巧和室友玩纸牌,想到小时候玩的24点游戏,所以当做练习,写了一段代码。
参考了一位叫GreatAnt网友的程序,但是他实现的只是一种计算结果的输出,为了看到所以计算可能的输出,我编写了下面一段代码,欢迎广大网友来此留言交流。
#!/usr/bin/env python
#encoding:utf8
import itertools
import random
cardNum = [] # 存放随机牌组
listSet = [] # 存放随机牌组对
cardGroup = () # 调用牌组
symbols = ["+","-","*","/"]
cardOne = 0 ; cardTwo = 0 ; cardThr = 0 ;cardFor = 0 # 存放卡牌信息
resultOne = 0 ; resultTwo = 0 ; resultThr = 0 # 存放运算计算结果
cardValue = [] # 保存结果打印信息
cardResult = []
# 发牌器
def cardFun():
for i in range(4):
cardNum.append(int(random.random() * 100 % 13) + 1)
listSet = list(set(itertools.permutations(cardNum, 4)))
return listSet # 存放A(4,4)种排列方式的列表
# 计算方法
cardList = cardFun()
def cardCompute():
for i in range(len(cardList)):
cardGroup = cardList[i]
cardOne = cardGroup[0]
cardTwo = cardGroup[1]
cardThr = cardGroup[2]
cardFor = cardGroup[3]
flag = False
# 下面的循环运算体系会有数学上逻辑上的报错,所以用try检测
try:
for s1 in symbols:
resultOne = 0
if s1 == "+":
resultOne = cardOne + cardTwo
elif s1 == "-":
resultOne = cardOne - cardTwo
elif s1 == "*":
resultOne = cardOne * cardTwo
elif s1 == "/":
resultOne = cardOne / cardTwo
for s2 in symbols:
resultTwo = 0
if s2 == "+":
resultTwo = resultOne + cardThr
elif s2 == "-":
resultTwo = resultOne - cardThr
elif s2 == "*":
resultTwo = resultOne * cardThr
elif s2 == "/":
resultTwo = resultOne / cardThr
for s3 in symbols:
resultThr =0 ; resultelse = 0
if s3 == "+":
resultThr = resultTwo + cardFor
resultelse = cardThr + cardFor
elif s3 == "-":
resultThr = resultTwo - cardFor
resultelse = cardThr - cardFor
elif s3 == "*":
resultThr = resultTwo * cardFor
resultelse = cardThr * cardFor
elif s3 == "/":
resultThr = resultTwo / cardFor
resultelse = cardThr / cardFor
# 判断最终结果是否为24
if resultThr == 24:
cardValue.append("((%s %s %s) %s %s ) %s %s = 24" % (cardOne,s1,cardTwo,s2,cardThr,s3,cardFor))
flag = True
# 括号与括号的运算
elif resultThr != 24 and 24 % resultOne == 0:
for s4 in symbols:
resultThr = 0
if s4 == "+":
resultThr = resultOne + resultelse
elif s4 == "-":
resultThr = resultOne - resultelse
elif s4 == "*":
resultThr = resultOne * resultelse
elif s4 == "/":
resultThr = resultOne / resultelse
if resultThr == 24:
cardValue.append("(%s %s %s) %s (%s %s %s) = 24" % (cardOne,s1,cardTwo,s4,cardThr,s3,cardFor))
flag = True
if flag:
break
# 如果得到结果,就退出3次运算的循环
if flag:
break
if flag:
break
if flag:
break
except ZeroDivisionError:
pass
cardResult = set(cardValue)
return cardResult
# 执行主体
if __name__ == "__main__":
Compute = cardCompute()
print("你手上的卡牌为:%s %s %s %s" % (cardList[0][0],cardList[0][1],cardList[0][2],cardList[0][3]))
print("这组卡牌共有 %s 种算法" % (len(Compute)))
print("---" * 10)
for i in Compute:
print(i)
此程序的实现没什么算法上的设计,就是用穷举法简单粗暴的来解决,因为是初学,所以主要是练习数据类型的应用,欢迎指错。