博客园  :: 首页  :: 新随笔  :: 联系 :: 订阅 订阅  :: 管理

[HDU][4007][Dave]

Posted on 2011-09-07 23:43  紫华弦筝  阅读(145)  评论(0编辑  收藏  举报

题目:http://acm.hdu.edu.cn/showproblem.php?pid=4007

给定一些点和一个正方形,求正方形能圈住的最多点数。

参考了P103的黑书。 

 

View Code
#include <stdio.h>
#include
<algorithm>

using namespace std;

typedef
struct
{
int x, y;
} point;

bool cmp(point a, point b)
{
if (a.x == b.x) return a.y < b.y;
return a.x < b.x;
}

bool cmp2(point a, point b)
{
if (a.x == b.x) return a.y > b.y;
return a.x < b.x;
}

point a[
1000+5];
point b[
10000];

int main(void)
{
//freopen("D:/a.txt", "r", stdin);
int n, r;
while (scanf("%d%d", &n, &r)!=EOF)
{
for (int i=0; i<1000; i++)
{
a[i].x
= 1000000001;
}
for (int i=0; i<n; i++)
{
scanf(
"%d%d", &a[i].x, &a[i].y);
}
sort(a, a
+ n, cmp);

int top=0, max = 0;
for (int i=0; i<n; i++)
{
int max2 = 0;

top
=0;
int sta = a[i].x, ed = a[i].x + r;
for (int j=0; j<n; j++)
{
if (a[j].x < sta || a[j].x > ed) continue;
b[top].x
= a[j].y;
b[top].y
= 1;
top
++;
b[top].x
= a[j].y + r + 1;
b[top].y
= -1;
top
++;
}

sort(b, b
+top, cmp2);
int sum = 0;
for (int i=0; i<top; i++)
{
sum
+= b[i].y;
max2
= max2 > sum ? max2 : sum;
}

max
= max > max2 ? max : max2;
}
printf(
"%d\n", max);
}
return 0;
}