04 Transformer 中的位置编码的 Pytorch 实现

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class PositionalEncoding(nn.Module):

    def __init__(self, dim, dropout, max_len=5000):
        super(PositionalEncoding, self).__init__()

        if dim % 2 != 0:
            raise ValueError("Cannot use sin/cos positional encoding with "
                             "odd dim (got dim={:d})".format(dim))

        """
        构建位置编码pe
        pe公式为:
        PE(pos,2i/2i+1) = sin/cos(pos/10000^{2i/d_{model}})
        """
        pe = torch.zeros(max_len, dim)  # max_len 是解码器生成句子的最长的长度,假设是 10
        position = torch.arange(0, max_len).unsqueeze(1)
        div_term = torch.exp((torch.arange(0, dim, 2, dtype=torch.float) *
                              -(math.log(10000.0) / dim)))


        pe[:, 0::2] = torch.sin(position.float() * div_term)
        pe[:, 1::2] = torch.cos(position.float() * div_term)
        pe = pe.unsqueeze(1)
        self.register_buffer('pe', pe)
        self.drop_out = nn.Dropout(p=dropout)
        self.dim = dim

    def forward(self, emb, step=None):

        emb = emb * math.sqrt(self.dim)

        if step is None:
            emb = emb + self.pe[:emb.size(0)]
        else:
            emb = emb + self.pe[step]
        emb = self.drop_out(emb)
        return emb

posted @ 2022-07-28 19:55  B站-水论文的程序猿  阅读(1832)  评论(0编辑  收藏  举报