POJ 1002 - 487-3279 STL

先把不是标准格式的字符串变成标准格式
再输出出现两次以上的标准串和出现的次数
不然输出 "No duplicates."

 1 #include <iostream>
 2 #include <cstring>
 3 #include <string>
 4 #include <map>
 5 #include <vector>
 6 #include <algorithm>
 7 using namespace std;
 8 int n;
 9 map<char,char> num;
10 map<string,int> mp;
11 string a;
12 char s[100005];
13 vector<string> ans;
14 int main()
15 {
16     num.clear();
17     mp.clear();
18     ans.clear();
19     num['A'] = num['B'] = num['C'] = '2';
20     num['D'] = num['E'] = num['F'] = '3';
21     num['G'] = num['H'] = num['I'] = '4';
22     num['J'] = num['K'] = num['L'] = '5';
23     num['M'] = num['N'] = num['O'] = '6';
24     num['P'] = num['R'] = num['S'] = '7';
25     num['T'] = num['U'] = num['V'] = '8';
26     num['W'] = num['X'] = num['Y'] = '9';
27     cin>>n;
28     for (int i = 1; i <= n; i++)
29     {
30         a.clear();
31         cin>>s;
32         for (int i = 0; s[i] != '\0'; i++)
33         {
34             if(s[i]>='0' && s[i]<='9') a+=s[i];
35             else if(s[i] >= 'A' && s[i] <= 'Z' && s[i] != 'Q' && s[i] != 'Z')
36                 a+= num[s[i]];
37             if(a.length() == 3) a+='-';
38         }
39         if(a.length() == 8)
40         {
41             mp[a]++;
42             if(mp[a] == 2) ans.push_back(a);
43         }
44     }
45     sort(ans.begin(), ans.end());
46     if(ans.size() == 0)
47     {
48         cout<<"No duplicates."<<endl;
49     }
50     else
51     {
52         for (int i = 0; i < ans.size(); i++){
53             cout<<ans[i]<<" "<<mp[ans[i]]<<endl;
54         }        
55     }
56 }

 

posted @ 2016-08-13 14:06  nicetomeetu  阅读(139)  评论(0)  编辑  收藏  举报