Assign the task HDU - 3974

原题链接
考察:线段树
思路:
  线段树染色+dfs序. 关于dfs序的讲解GO!

Code

#include <iostream> 
#include <cstring>
using namespace std;
const int N = 50010;
int n,sz[N],h[N],idx,root,k,id[N],m,fa[N];
char s[3];
struct Road{
	int fr,to,ne;
}road[N];
struct Node{
	int l,r,c,tag;
}tr[N<<2];
void init()
{
	memset(sz,0,sizeof sz); k = 0;
	memset(fa,0,sizeof fa);
}
void add(int a,int b)
{
	road[idx].to = b,road[idx].ne = h[a],h[a] = idx++;
}
int dfs(int u)
{
	id[u] = ++k; sz[u] = 1; 
	for(int i=h[u];~i;i=road[i].ne)
	{
		int v = road[i].to;
		sz[u]+=dfs(v);
	}
	return sz[u];
}
void push_up(int u)
{   
	if(tr[u<<1].c!=tr[u<<1|1].c) tr[u].c = -1;
	else tr[u].c = tr[u<<1].c;
}
void push_down(int u)
{
	if(tr[u].c!=-1)
	{
		tr[u<<1].c = tr[u].c;
		tr[u<<1|1].c = tr[u].c;
	}
}
void build(int u,int l,int r)
{
	tr[u] = {l,r,0,0};
	if(l==r) return;
	int mid = l+r>>1;
	build(u<<1,l,mid); build(u<<1|1,mid+1,r);
}
void modify(int u,int l,int r,int x)
{
	if(tr[u].l>=l&&tr[u].r<=r)
	{
		tr[u].c = x;
		tr[u].tag = x;
		return;
	}
	push_down(u);
	int mid = tr[u].l+tr[u].r>>1;
	if(l<=mid) modify(u<<1,l,r,x);
	if(mid<r) modify(u<<1|1,l,r,x);
	push_up(u);
}
int query(int u,int idx)
{
	if(tr[u].l<=idx&&tr[u].r>=idx&&tr[u].c!=-1) return tr[u].c;
	if(tr[u].l==tr[u].r) return tr[u].c;
	push_down(u);
	int mid = tr[u].l+tr[u].r>>1;
	if(idx<=mid) return query(u<<1,idx);
	else return query(u<<1|1,idx);
}
int main()
{
	int T,kcase = 0;
	scanf("%d",&T);
	while(T--)
	{
		init();
		printf("Case #%d:\n",++kcase);
		scanf("%d",&n); idx = 0;
		for(int i=1;i<=n;i++) h[i] = -1;
		for(int i=1;i<n;i++)
		{
			int u,v; scanf("%d%d",&u,&v);
			add(v,u);
			fa[u] = v;
		}
		for(int i=1;i<=n;i++) if(!fa[i]) {root=i;break;} 
		dfs(root);
		build(1,1,n);
		scanf("%d",&m);
		while(m--)
		{
			int x,y;
			scanf("%s%d",s,&x);
			if(s[0]=='C')
			{
				int c = query(1,id[x]);
				if(!c) puts("-1");
				else printf("%d\n",c-1);
				continue;
			}
			scanf("%d",&y);
			y++;
			modify(1,id[x],id[x]+sz[x]-1,y);
		}
	}
	return 0;
}
posted @ 2021-05-22 02:57  acmloser  阅读(29)  评论(0编辑  收藏  举报