noip2014day2

T1

直接枚举位置,暴力过.

#include <stdio.h>
#include <algorithm>
#include <cstring>
#include <cmath>
#include <queue>
#include <vector>
using namespace std;
int d,n,ans,f,m[130][130];
template <class T> void read(T&x)
{
  x=0;char c=getchar();int f=0;
  while(c<'0'||c>'9'){f|=(c=='-');c=getchar();}
  while(c>='0'&&c<='9')x=(x<<3)+(x<<1)+(c^=48),c=getchar();
  x=f?-x:x;
}
int dfs(int x,int y)
{
  int sum=0;
  for(int i=x-d;i<=x+d;i++)
   for(int j=y-d;j<=y+d;j++)
   {
        if(i<1||j<1||i>129||j>129)continue;
        sum+=m[i][j];
   }
   return sum;
} 
int main()
{
  freopen("wireless.in","r",stdin);
  freopen("wireless.out","w",stdout);
  memset(m,0,sizeof(m));
  read(d);read(n);
  int x,y,k;
  for(register int i=1;i<=n;i++)
  {
      read(x);read(y);read(k);
      m[x+1][y+1]=k;
  }
  int t;
  for(int i=1;i<=129;i++)
   for(int j=1;j<=129;j++)
   {
        t=dfs(i,j);
        if(t>ans)ans=t,f=1;
        else if(t==ans)f++;
   }
  printf("%d %d",f,ans);
  fclose(stdin);
  fclose(stdout);
  return 0;
}
View Code

T2

正反都建边;

反向bfs能到的点,然后正向跑spfa。(居然T了一个点)

#include <stdio.h>
#include <algorithm>
#include <cstring>
#include <cmath>
#include <queue>
#include <vector>
using namespace std;
const int maxn=10000+10;
const int maxm=200000+10;
const int inf=0x7f/3;
struct hh
{
  int v,next;
}e[maxm];
hh a[maxm];
int n,m,point,s,t;
int head[maxn],vis[maxn],dis[maxn],head2[maxn],gou[maxn],c[maxn];
template <class T> void read(T&x)
{
  x=0;char c=getchar();int f=0;
  while(c<'0'||c>'9'){f|=(c=='-');c=getchar();}
  while(c>='0'&&c<='9')x=(x<<3)+(x<<1)+(c^=48),c=getchar();
  x=f?-x:x;
}
void bfs(int s)
{
  queue<int>p;
  memset(c,0,sizeof(c));
  p.push(s);vis[s]=1;
  while(!p.empty())
  {
      int x=p.front();p.pop();vis[x]=0;
      gou[x]=1;
      for(int i=head2[x];i!=-1;i=a[i].next)
      {
        if(++c[a[i].v]>n||vis[a[i].v])continue;
        p.push(a[i].v);
      vis[a[i].v]=1;
      }
  }
  return;
}
int pan(int x)
{
  for(int i=head[x];i!=-1;i=e[i].next)if(!gou[e[i].v])return 0;
  return 1;
}
void spfa(int p)
{
  queue<int>q;
  memset(vis,0,sizeof(vis));
  memset(dis,inf,sizeof(dis));
  memset(c,0,sizeof(c));
  vis[p]=1;q.push(p);dis[p]=0;
  while(!q.empty())
  {
      int x=q.front();q.pop();vis[x]=0;
      for(int i=head[x];i!=-1;i=e[i].next)
      {
        int y=e[i].v;
        if(pan(y)&&dis[y]>dis[x]+1)
        {
            dis[y]=dis[x]+1;
            if(!vis[y])
            {
         if(++c[y]>n)continue;
              q.push(y);
              vis[y]=1;
            }
        }
      }
  }
  return;
}
void add(int u,int v){e[++point].v=v;e[point].next=head[u];head[u]=point;}
void add1(int u,int v){a[point].v=v;a[point].next=head2[u];head2[u]=point;}
int main()
{
  freopen("road.in","r",stdin);
  freopen("road.out","w",stdout);
  memset(head,-1,sizeof(head));
  memset(head2,-1,sizeof(head2));
  read(n);read(m);
  int u,v;
  for(register int i=1;i<=m;i++)
  {
      read(u);read(v);
      add(u,v);add1(v,u);
  }
  read(s);read(t);
  bfs(t);
  spfa(s);
  if(dis[t]==707406378)printf("-1");
  else printf("%d",dis[t]);
  fclose(stdin);
  fclose(stdout);
  return 0;
}
View Code

T3

枚举解,选几个质数带进去%一下就过了(5-6)

#include<iostream>
#include<cstdio>
#include<cstring>
#include<cstdlib>
#include<cmath>
#include<algorithm>
using namespace std;
int read()
{
    int x=0,f=1;char ch=getchar();
    while(ch<'0'||ch>'9'){if(ch=='-')f=-1;ch=getchar();}
    while(ch>='0'&&ch<='9'){x=x*10+ch-'0';ch=getchar();}
    return x*f;
}
int mod[5]={11261,19997,22877,21893,14843};
int n,m;
int ans[1000005];
int a[5][105],pre[5][105],res[5][30005];
char ch[10005];
inline int cal(int t,int x)
{
    int sum=0;
    for(int i=0;i<=n;i++)
        sum=(sum+a[t][i]*pre[t][i])%mod[t];
    if(sum<0)sum+=mod[t];
    return sum;
}
inline bool jud(int x)
{
    for(int t=0;t<5;t++)
        if(res[t][x%mod[t]]!=0)return 0;
    return 1;
}
int main()
{
    n=read();m=read();
    for(int i=0;i<=n;i++)
    {
        scanf("%s",ch+1);
        int l=strlen(ch+1);
        bool flag=0;
        for(int t=0;t<5;t++)
            if(ch[1]!='-')a[t][i]=ch[1]-'0';
            else a[t][i]=0,flag=1;
        for(int t=0;t<5;t++)
        {
            for(int k=2;k<=l;k++)
                a[t][i]=(a[t][i]*10+ch[k]-'0')%mod[t];
            if(flag)a[t][i]=-a[t][i];
        }
    }
    for(int t=0;t<5;t++)
        for(int x=1;x<mod[t];x++)
        {
            pre[t][0]=1;
            for(int i=1;i<=n;i++)pre[t][i]=(pre[t][i-1]*x)%mod[t];
            res[t][x]=cal(t,x);
        }
    for(int i=1;i<=m;i++)
        if(jud(i))ans[++ans[0]]=i;
    printf("%d\n",ans[0]);
    for(int i=1;i<=ans[0];i++)
        printf("%d\n",ans[i]);
    return 0;
}
View Code

 

posted @ 2017-10-23 17:38  新手-周  阅读(135)  评论(0编辑  收藏  举报