JAVA处理数字与中文数字互转(最大处理数字不超过万兆即:9999999999999999.9999)
package practice; import java.util.Arrays; /** * 数字与中文数字互转(最大处理数字不超过万兆即:9999999999999999.9999) * @author Archimedes * @Date 6 7 19 */ public class ChineseNumberAndNumber { private static final char NUMBER_CONSTRAINT[] = {'9', '8', '7', '6', '5', '4', '3', '2', '1', '0', '.'}; private static final String[] DECIMAL_UNIT = {"角", "分", "厘", "毫"}; private static final String[] CHINESE_NUMBER = {"零", "壹", "贰", "叁", "肆", "伍", "陆", "柒", "捌", "玖"}; private static final String[] INTEGER_UNIT = {"", "万", "亿", "兆"}; private static final String[] INTEGER_UNIT1 = {"", "拾", "佰", "仟"}; /** * 数字转中文数字 * @param number * @return */ public static String numberToChineseNumber(String number) { //数字有效性判断 //先判断number中的数字是否在NUMBER_CONSTRAINT[]中 int quantity = NUMBER_CONSTRAINT.length - 1; for (int i = 0; i < number.length(); i++) { char unit = number.charAt(i); for (int j = 0; j < NUMBER_CONSTRAINT.length; j++) { if (unit == NUMBER_CONSTRAINT[j]) break; if (j == quantity) return "请输入有效数字"; } } //再判断number中小数点是否不超过1个且小数点不在第一位和最后一位 int quantity1 = 0; for (int i = 0; i < number.length(); i++) { if ('.' == number.charAt(i) && (i == 0 || i == number.length() - 1)) return "1请输入有效数字"; if ('.' == number.charAt(i)) { ++quantity1; if (quantity1 == 2) return "2请输入有效数字"; } } //最后做数字范围的有效判断,并且把诸如0.000000000000000的数字转换为0 if (quantity1 == 0) { number = headNumberIsZero(number); if (number.length() > 16) return "3请输入有效数字"; } else { String[] split = number.split("[.]"); //处理整数部分 split[0] = headNumberIsZero(split[0]); if (split[0].length() > 16) return "4请输入有效数字"; //处理小数部分 if (split[1].length() > 4) { for (int i = 4; i < split[1].length(); i++) { if ('0' != split[1].charAt(i)) return "5请输入有效数字"; } split[1] = split[1].substring(0, 4); } for (int i = split[1].length() - 1; i >= 0; i--) { if ('0' == split[1].charAt(i)) split[1] = split[1].substring(0, i); else break; } //合并整数与小数 if (split[1].isEmpty()) number = split[0]; else number = split[0] + "." + split[1]; } //数字有效性判断完毕 //数字转中文数字 String[] result = {"", ""}; String[] split = number.split("[.]"); //处理小数部分 if (split.length == 2) { int c = 0; //定义标识用于判断前一位是否为0 for (int i = 0; i < split[1].length(); i++) { if (c == 0 && ('0' == split[1].charAt(i))) { result[1] += CHINESE_NUMBER[0]; c = 1; } else if ('0' != split[1].charAt(i)) { result[1] += (CHINESE_NUMBER[Integer.parseInt(String.valueOf(split[1].charAt(i)))] + DECIMAL_UNIT[i]); c = 0; } } } //处理整数部分 //把整数部分从左到右每4个一组放入数组 String[] integerPart = new String[(split[0].length() - 1) / 4 + 1]; for (int i = split[0].length() - 1; i >= 0; i -= 4) { if (i - 3 >= 0) integerPart[i / 4] = split[0].substring(i - 3, i + 1); else integerPart[i / 4] = split[0].substring(0, i + 1); } System.out.println(Arrays.toString(integerPart)); //转换 int length = integerPart.length; int c = 0; //用于判断前一位是否为0 if (length > 1) { int l = 1; ////用于判断上一次计数单位是否全为0(0表示全为0) for (int i = 0; i < integerPart.length; i++) { int x = 0; //用于判断计数单位是否全为0 int length1 = integerPart[i].length(); for (int j = 0; j < length1; j++) { if (c == 0 && '0' != integerPart[i].charAt(j)) { String temp = CHINESE_NUMBER[Integer.parseInt(String.valueOf(integerPart[i].charAt(j)))] + INTEGER_UNIT1[length1 - 1 -j]; result[0] += temp; x = 1; } else if ('0' == integerPart[i].charAt(j)) { c = 1; } else if (c == 1 && j == 0 && '0' != integerPart[i].charAt(j)) { if (l == 0) result[0] += "零"; String temp = CHINESE_NUMBER[Integer.parseInt(String.valueOf(integerPart[i].charAt(j)))] + INTEGER_UNIT1[length1 - 1 -j]; result[0] += temp; c = 0; x = 1; } else if (c == 1 && j != 0 && '0' != integerPart[i].charAt(j)) { String temp = "零" + CHINESE_NUMBER[Integer.parseInt(String.valueOf(integerPart[i].charAt(j)))] + INTEGER_UNIT1[length1 - 1 -j]; result[0] += temp; c = 0; x = 1; } } l = x; //把此次循环的计数单位是否全为0的结果赋值给变量,用于下次循环判断 if (x == 1) result[0] += INTEGER_UNIT[length - 1 - i]; } result[0] += "元"; } else { int length1 = integerPart[0].length(); for (int i = 0; i < length1; i++) { if (c == 0 && ('0' != integerPart[0].charAt(i))) { String temp = CHINESE_NUMBER[Integer.parseInt(String.valueOf(integerPart[0].charAt(i)))] + INTEGER_UNIT1[length1 - 1 - i]; result[0] += temp; } else if ('0' == integerPart[0].charAt(i)) { if (length1 == 1) { result[0] += "零"; } c = 1; } else if (c == 1 && ('0' != integerPart[0].charAt(i))) { String temp = "零" + CHINESE_NUMBER[Integer.parseInt(String.valueOf(integerPart[0].charAt(i)))] + INTEGER_UNIT1[length1 - 1 - i]; result[0] += temp; c = 0; } } result[0] += "元"; } if (split.length == 1) { result[0] += "整"; return result[0]; } else { if ("零元".equals(result[0])) return result[1]; else return result[0] + result[1]; } //数字转中文数字完毕 } /** * 把数字的前几个连续的0去掉,但数字如全为0则保留1个 * @param number * @return */ private static String headNumberIsZero(String number) { try { if ('0' == number.charAt(0)) return headNumberIsZero(number.substring(1)); else return number; } catch (IndexOutOfBoundsException e) { return "0"; } } private static String headNumberIsZero1(String number) { if (number.isEmpty()) return "0"; if ('0' == number.charAt(0)) return headNumberIsZero(number.substring(1)); else return number; } private static String headNumberIsZero2(String number) { if ('0' != number.charAt(0)) return number; else { for (int i = 1; i < number.length(); i++) { if ('0' != number.charAt(i)) { number = number.substring(i); break; } else if (i == number.length() -1) number = "0"; } } return number; } public static void main(String[] args) { String number = numberToChineseNumber("64646405000.033"); System.out.println(number); } }