JAVA处理数字与中文数字互转(最大处理数字不超过万兆即:9999999999999999.9999)

package practice;

import java.util.Arrays;

/**
 * 数字与中文数字互转(最大处理数字不超过万兆即:9999999999999999.9999)
 * @author Archimedes
 * @Date 6 7 19
 */
public class ChineseNumberAndNumber {
    
    private static final char NUMBER_CONSTRAINT[] = {'9', '8', '7', '6', '5', '4', '3', '2', '1', '0', '.'};
    
    private static final String[] DECIMAL_UNIT = {"角", "分", "厘", "毫"};
    
    private static final String[] CHINESE_NUMBER = {"零", "壹", "贰", "叁", "肆", "伍", "陆", "柒", "捌", "玖"};
    
    private static final String[] INTEGER_UNIT = {"", "万", "亿", "兆"};
    
    private static final String[] INTEGER_UNIT1 = {"", "拾", "佰", "仟"};
    
    /**
     * 数字转中文数字
     * @param number
     * @return
     */
    public static String numberToChineseNumber(String number) {
        //数字有效性判断
        //先判断number中的数字是否在NUMBER_CONSTRAINT[]中
        int quantity = NUMBER_CONSTRAINT.length - 1;
        for (int i = 0; i < number.length(); i++) {
            char unit = number.charAt(i);
            for (int j = 0; j < NUMBER_CONSTRAINT.length; j++) {
                if (unit == NUMBER_CONSTRAINT[j]) break;
                if (j == quantity) return "请输入有效数字";
            }
        }
        //再判断number中小数点是否不超过1个且小数点不在第一位和最后一位
        int quantity1 = 0;
        for (int i = 0; i < number.length(); i++) {
            if ('.' == number.charAt(i) && (i == 0 || i == number.length() - 1)) return "1请输入有效数字";
            if ('.' == number.charAt(i)) {
                ++quantity1;
                if (quantity1 == 2) return "2请输入有效数字";
            }
        }
        //最后做数字范围的有效判断,并且把诸如0.000000000000000的数字转换为0
        if (quantity1 == 0) {
            number = headNumberIsZero(number);
            if (number.length() > 16) return "3请输入有效数字";
        } else {
            String[] split = number.split("[.]");
            //处理整数部分
            split[0] = headNumberIsZero(split[0]);
            if (split[0].length() > 16) return "4请输入有效数字";
            //处理小数部分
            if (split[1].length() > 4) {
                for (int i = 4; i < split[1].length(); i++) {
                    if ('0' != split[1].charAt(i)) return "5请输入有效数字";
                }
                split[1] = split[1].substring(0, 4);
            }
            for (int i = split[1].length() - 1; i >= 0; i--) {
                if ('0' == split[1].charAt(i)) split[1] = split[1].substring(0, i);
                else break;
            }
            //合并整数与小数
            if (split[1].isEmpty()) number = split[0];
            else number = split[0] + "." + split[1];
        }
        //数字有效性判断完毕
        
        //数字转中文数字
        String[] result = {"", ""};
        String[] split = number.split("[.]");
        //处理小数部分
        if (split.length == 2) {
            int c = 0; //定义标识用于判断前一位是否为0
            for (int i = 0; i < split[1].length(); i++) {
                if (c == 0 && ('0' == split[1].charAt(i))) {
                    result[1] += CHINESE_NUMBER[0];
                    c = 1;
                } else if ('0' != split[1].charAt(i)) {
                    result[1] += (CHINESE_NUMBER[Integer.parseInt(String.valueOf(split[1].charAt(i)))] + DECIMAL_UNIT[i]);
                    c = 0;
                }
            }
        }
        //处理整数部分
        //把整数部分从左到右每4个一组放入数组
        String[] integerPart = new String[(split[0].length() - 1) / 4 + 1];
        for (int i = split[0].length() - 1; i >= 0; i -= 4) {
            if (i - 3 >= 0) integerPart[i / 4] = split[0].substring(i - 3, i + 1);
            else integerPart[i / 4] = split[0].substring(0, i + 1);
        }
        System.out.println(Arrays.toString(integerPart));
        //转换
        int length = integerPart.length;
        int c = 0; //用于判断前一位是否为0
        if (length > 1) {
            int l = 1; ////用于判断上一次计数单位是否全为0(0表示全为0)
            for (int i = 0; i < integerPart.length; i++) {
                int x = 0; //用于判断计数单位是否全为0
                int length1 = integerPart[i].length();
                for (int j = 0; j < length1; j++) {
                    if (c == 0 && '0' != integerPart[i].charAt(j)) {
                        String temp = CHINESE_NUMBER[Integer.parseInt(String.valueOf(integerPart[i].charAt(j)))]
                                + INTEGER_UNIT1[length1 - 1 -j];
                        result[0] += temp;
                        x = 1;
                    } else if ('0' == integerPart[i].charAt(j)) {
                        c = 1;
                    } else if (c == 1 && j == 0 && '0' != integerPart[i].charAt(j)) {
                        if (l == 0) result[0] += "零";
                        String temp = CHINESE_NUMBER[Integer.parseInt(String.valueOf(integerPart[i].charAt(j)))]
                                + INTEGER_UNIT1[length1 - 1 -j];
                        result[0] += temp;
                        c = 0; x = 1;
                    } else if (c == 1 && j != 0 && '0' != integerPart[i].charAt(j)) {
                        String temp = "零" + CHINESE_NUMBER[Integer.parseInt(String.valueOf(integerPart[i].charAt(j)))]
                                + INTEGER_UNIT1[length1 - 1 -j];
                        result[0] += temp;
                        c = 0; x = 1;
                    }
                }
                l = x; //把此次循环的计数单位是否全为0的结果赋值给变量,用于下次循环判断
                if (x == 1) result[0] += INTEGER_UNIT[length - 1 - i];
            }
            result[0] += "元";
        } else {
            int length1 = integerPart[0].length();
            for (int i = 0; i < length1; i++) {
                if (c == 0 && ('0' != integerPart[0].charAt(i))) {
                    String temp = CHINESE_NUMBER[Integer.parseInt(String.valueOf(integerPart[0].charAt(i)))]
                            + INTEGER_UNIT1[length1 - 1 - i];
                    result[0] += temp;
                } else if ('0' == integerPart[0].charAt(i)) {
                    if (length1 == 1) {
                        result[0] += "零";
                    }
                    c = 1;
                } else if (c == 1 && ('0' != integerPart[0].charAt(i))) {
                    String temp = "零" + CHINESE_NUMBER[Integer.parseInt(String.valueOf(integerPart[0].charAt(i)))]
                            + INTEGER_UNIT1[length1 - 1 - i];
                    result[0] += temp;
                    c = 0;
                }
            }
            result[0] += "元";
        }
        if (split.length == 1) {
            result[0] += "整";
            return result[0];
        } else {
            if ("零元".equals(result[0])) return result[1];
            else return result[0] + result[1];
        }
        //数字转中文数字完毕
    }
    
    /**
     * 把数字的前几个连续的0去掉,但数字如全为0则保留1个
     * @param number
     * @return
     */
    private static String headNumberIsZero(String number) {
        try {
            if ('0' == number.charAt(0)) return headNumberIsZero(number.substring(1));
            else return number;
        } catch (IndexOutOfBoundsException e) {
            return "0";
        }
    }
    
    private static String headNumberIsZero1(String number) {
        if (number.isEmpty()) return "0";
        if ('0' == number.charAt(0)) return headNumberIsZero(number.substring(1));
        else return number;
    }
    
    private static String headNumberIsZero2(String number) {
        if ('0' != number.charAt(0)) return number;
        else {
            for (int i = 1; i < number.length(); i++) {
                if ('0' != number.charAt(i)) {
                    number = number.substring(i);
                    break;
                } else if (i == number.length() -1) number = "0";
            }
        }
        return number;
    }
    
    public static void main(String[] args) {
        String number = numberToChineseNumber("64646405000.033");
        System.out.println(number);
    }
    
}

 

posted @ 2019-08-14 15:40  接近风的地方  阅读(1600)  评论(0编辑  收藏  举报