Uva--10361 (字符串处理）

2014-05-29 17:22:16

题目链接：http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=15&page=show_problem&problem=1302

题意：简单题，处理一下字符串即可，需要注意的是输入格式。

HUSTOJ提供了Hint，我用的是逐个如入char的方法

Hint：when u read a line of string after an int, u can use following codes, like

scanf("%d",&t);getchar();gets(str);

or   string str; cin>>t;getchar();getline(cin,str);

or u may read some unexpected words

#include <cstdio>
#include <stdio.h>
#include <string.h>
#include <cstring>
#include <iostream>
#include <fstream>
using namespace std;
const int maxn = 100;

int main(){
    char l1[maxn + 5],l2[maxn + 5];
    int n,len_l1,f[4];
    scanf("%d",&n);
    getchar();
    while(n--){
        int cnt = 0;
        len_l1 = 0;
        char t;
        while(scanf("%c",&t) == 1){
            if(t == '\n') break;
            if(t == '<' || t == '>'){
                f[cnt++] = len_l1;
            }
            else{
                l1[len_l1] = t;
                printf("%c",t);
            }
            ++len_l1;
        }
        puts("");
        while(scanf("%c",&t) == 1){
            if(t == '\n') break;
            else if(t != '.'){
                printf("%c",t);
            }
        }
        for(int i = f[2] + 1; i < f[3]; i++)
            printf("%c",l1[i]);
        for(int i = f[1] + 1; i < f[2]; i++)
            printf("%c",l1[i]);
        for(int i = f[0] + 1; i < f[1]; i++)
            printf("%c",l1[i]);
        for(int i = f[3] + 1; i < len_l1; i++)
            printf("%c",l1[i]);
        puts("");
    }
    return 0;
}