传送门
$\tt\huge十年\ OI\ 一场空,不开\ long\ long\ 见祖宗$
点击查看代码
#include <bits/stdc++.h>
using namespace std;
#define INF 0x3f3f3f3f
#define N 200010
#define ll long long
#define int128 __int128
//#define int long long
char buf[1<<21], *p1=buf, *p2=buf;
#define getchar() (p1==p2&&(p2=(p1=buf)+fread(buf, 1, 1<<21, stdin)), p1==p2?EOF:*p1++)
inline int read() {
int ans=0, f=1; char c=getchar();
while (!isdigit(c)) {if (c=='-') f=-f; c=getchar();}
while (isdigit(c)) {ans=(ans<<3)+(ans<<1)+(c^48); c=getchar();}
return ans*f;
}
// char obuf[N]; int otop;
// inline void writeln(int128 t) {
// otop=0;
// do {obuf[++otop]='0'+t%10; t/=10;} while (t);
// while (otop) printf("%c", obuf[otop--]);
// printf("\n");
// }
int n, m;
int a[5][N];
namespace force{
ll ans;
ll f(int i, int j) {
int mn=INF, mx=0;
for (int k=1; k<=m; ++k) {
mn=min(mn, a[k][i]+a[k][j]);
mx=max(mx, a[k][i]+a[k][j]);
}
return mn+mx;
}
void solve() {
for (int i=1; i<=n; ++i)
for (int j=1; j<=n; ++j)
ans+=f(i, j);
cout<<ans<<endl;
}
}
namespace task1{
ll ans;
void solve() {
for (int k=1; k<=2; ++k) {
ll sum=0;
for (int i=1; i<=n; ++i) sum+=a[k][i];
for (int i=1; i<=n; ++i) ans+=sum+1ll*n*a[k][i];
}
cout<<ans<<endl;
}
}
signed main()
{
freopen("sort.in", "r", stdin);
freopen("sort.out", "w", stdout);
m=read(); n=read();
for (int i=1; i<=m; ++i) for (int j=1; j<=n; ++j) a[i][j]=read();
if (m==2) task1::solve();
else force::solve();
return 0;
}