题解 破门而入
求一行第一类斯特林数
\(O(n^2)\) 能过
Code:
#include <bits/stdc++.h>
using namespace std;
#define INF 0x3f3f3f3f
#define N 3010
#define ll long long
//#define int long long
char buf[1<<21], *p1=buf, *p2=buf;
#define getchar() (p1==p2&&(p2=(p1=buf)+fread(buf, 1, 1<<21, stdin)), p1==p2?EOF:*p1++)
inline int read() {
int ans=0, f=1; char c=getchar();
while (!isdigit(c)) {if (c=='-') f=-f; c=getchar();}
while (isdigit(c)) {ans=(ans<<3)+(ans<<1)+(c^48); c=getchar();}
return ans*f;
}
int n, k;
const ll mod=998244353;
namespace task1{
ll s[N][N], ans;
void solve() {
s[0][0]=1;
for (int i=1; i<=n; ++i) {
for (int j=1; j<=k; ++j) {
s[i][j]=(s[i-1][j-1]+1ll*(i-1)*s[i-1][j])%mod;
}
}
for (int i=1; i<=k; ++i) ans=(ans+s[n][i])%mod;
printf("%lld\n", ans);
exit(0);
}
}
signed main()
{
freopen("broken.in", "r", stdin);
freopen("broken.out", "w", stdout);
n=read(); k=read();
task1::solve();
return 0;
}