从1-100之间找到所有相加为100的三个数字的组合

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function findAllThreeNumbers(sum, count, max) {   if (count === 0) {     return sum === 100 ? [[]] : [];   }   const results = [];   for (let i = Math.min(max, 100 - sum - count + 1); i >= 1; i--) {     const subResults = findAllThreeNumbers(sum + i, count - 1, i - 1);     for (const subResult of subResults) {       results.push([i, ...subResult]);     }   }   return results; }   const results = findAllThreeNumbers(0, 3, 100); if (results.length > 0) {   console.log(`Found ${results.length} combinations of three numbers that add up to 100:`);   for (const result of results) {     console.log(result);   } } else {   console.log("No three numbers found that add up to 100."); }

　　

 

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function findThreeNumbers(n, nums) {   if (n == 0 && nums.reduce((sum, num) => sum + num, 0) == 100) {     result.push(nums);   } else if (n > 0) {     for (let i = nums.length == 0 ? 1 : nums[nums.length-1]+1; i <= 100-n+1; i++) {       findThreeNumbers(n-1, nums.concat([i]));     }   } }   let result = []; findThreeNumbers(3, []); console.log(result);