1 #  list元素求和
2 sum = reduce(lambda x,y: x+y, mylist)
1 # 比较两个 lists 的元素是否完全一致
2 if all(x==y for x, y in zip(X, Y))
3     do something
1 # 按照 key 排列字典的元素，以libsvm格式输出
2 sorted(dd.keys())
3 sorted_dict = [(key, dd[key]) for key in sorted(dd.keys())]
4 # 以libsvm格式打印
5 print ' '.join([str(key)+':'+str(dd[key]) for key in sorted(dd.keys())])
1 # 按照 value 排序字典的元素
2 # 仅输出排序后的key
3 sorted_key = [key for key in sorted(dd, key=dd.get, reverse=True)]
4 # 仅输出排序后的字典
5 sorted_dict = [(key, dd[key]) for key in sorted(dd, key=dd.get, reverse=True)]
6 # 以libsvm格式打印字典
7 print ' '.join([str(key)+':'+str(dd[key]) for key in sorted(dd, key=dd.get, reverse=True)])
1 # get key intersection of two dictionaries
2 intersect = set(dict_A.keys()) & set(dict_B.keys()) 
1 # sort a list of tuple
2 # 以tuple的第零个元素排序
3 sorted_list = sorted(tuple_list, key=lambda x:x[0])
1 # 把libsvm格式数据转换为dict对象
2 mydict = {x.split(':')[0]:x.split(':')[1] for x in mylist} 
1 # sort list and return index of list
2 # 对list排序，返回有序元素的原始下标值
3 sorted_index = sorted(range(len(list)), key=lambda k: list[k])