判断时间格式是否正确的代码
2007-09-14 19:07 Zhuang miao 阅读(1096) 评论(0) 编辑 收藏 举报分别用C#,C++,Vb代码实现了一下,感觉这段代码还算精炼有更优秀的还请指教!!
c#
using System;
using System.Collections.Generic;
using System.Text;
namespace isdata
{
class dataa
{
public static bool IsData(int y, int m, int d)
{
if (y <= 1000 || y >= 10000) return false;
if (m < 1 || m > 12) return false;
int[] month =new int[12] {31,0,31,30,31,30,31,31,30,31,30,31};
if (y % 4 == 0 && y % 100 != 0 || y % 400 == 0)
month[1] = 29;
else
month[1] = 28;
return (d>=1)&&(d<=month[m-1]);
}
}
}
VB
Imports System
Imports System.Collections.Generic
Imports System.Text
Namespace isdata
Class dataa
Public Shared Function IsData(ByVal y As Integer, ByVal m As Integer, ByVal d As Integer) As Boolean
If y <= 1000 Or y >= 10000 Then
Return False
End If
If m < 1 Or m > 12 Then
Return False
End If
Dim month() As Integer = New Integer(12) {31,0,31,30,31,30,31,31,30,31,30,31}
If y % 4 = Decimal.Remainder( 0 And y , 100 )<> 0 Or y % 400 = 0 Then
month(1) = 29
Else
month(1) = 28
End If
Return (d>=1)&&(d<=month(m-1))
End Function
End Class
End Namespace
c++
bool legalday(int y,int m,int d)
{ if(y<=0) return false;
if(m<1||m>12) return false;
int month[]=
{31,0,31,30,31,30,31,31,30,31,30,31};
if(y%4==0&&y%100!=0 || y%400==0)
month[1]=29;
else month[1]=28;
return (d>=1)&&(d<=month[m-1]);
}