九、action交给spring管理

1.在struts-config.xml中，配置代理请求

 

<!-- 不配置代理请求处理,收到login.do的请求后，web服务器查询web.xml把请求交给ActionServlet, ActionServlet查询struts-config.xml，填充表单并交给对应Action-->
    <!-- 配置代理请求处理,收到login.do的请求后，web服务器查询web.xml把请求交给ActionServlet, ActionServlet查询struts-config.xml，发现struts-config.xml中配置了代理请求处理，就去applicationContext.xml中寻找应该找哪个action-->
    <controller>
        <set-property value="processorClass" property="org.springframework.web.struts.DelegatingRequestProcessor"/>
    </controller>

 

 

2.loginAction中，将employeeService作为属性注入

　　2.1编辑loginAction，抽取出employeeService

package com.myz.web.actions;

import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

import org.apache.struts.action.ActionForm;
import org.apache.struts.action.ActionForward;
import org.apache.struts.action.ActionMapping;
import org.apache.struts.actions.DispatchAction;

import com.myz.domain.Employee;
import com.myz.service.interfaces.EmployeeServiceInterface;
import com.myz.web.forms.EmployeeForm;

public class LoginAction extends DispatchAction {
    private EmployeeServiceInterface employeeService;

    public EmployeeServiceInterface getEmployeeService() {
        return employeeService;
    }
    public void setEmployeeService(EmployeeServiceInterface employeeService) {
        this.employeeService = employeeService;
    }


public ActionForward login(ActionMapping mapping, ActionForm form,
            HttpServletRequest request, HttpServletResponse response) throws Exception {
        
        EmployeeForm employeeForm=(EmployeeForm) form;
        Employee e=new Employee();
        e.setId(employeeForm.getId());
        e.setPassword(employeeForm.getPassword());

        Employee loginUser=employeeService.loginCheck(e);
        
        if(loginUser!=null){
            //登录成功则保存用户信息到session中
            request.getSession().setAttribute("loginUser", loginUser);
            return mapping.findForward("ok");
        }else{
            return mapping.findForward("err");
        }
    }
}

　　2.2 applicationContext.xml中配置action

 

<!-- 配置action 而且配置scope可以解决action的单例的问题-->
    <bean name="/login" class="com.myz.web.actions.LoginAction" scope="prototype">
        <property name="employeeService" ref="employeeService"></property>
    </bean>

 

　　2.3 action中type的配置信息可以移除

<action path="/login" parameter="flag" name="employeeForm">
            <forward name="ok" path="/WEB-INF/mainFrame.jsp"></forward>
            <forward name="err" path="/WEB-INF/login.jsp"></forward>
        </action>

 

3.测试，输入正确用户id和密码能够登录，否则不能