七、整合struts

1.在WEB-INF目录下新建login.jsp并编辑处理

  1.1编辑login.jsp

<%@ page language="java" import="java.util.*" pageEncoding="utf-8"%>
<%
String path = request.getContextPath();
String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";
%>

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
  <head>
    <base href="<%=basePath%>">
    
    <title>My JSP 'login.jsp' starting page</title>
    
    <meta http-equiv="pragma" content="no-cache">
    <meta http-equiv="cache-control" content="no-cache">
    <meta http-equiv="expires" content="0">    
    <meta http-equiv="keywords" content="keyword1,keyword2,keyword3">
    <meta http-equiv="description" content="This is my page">
    <!--
    <link rel="stylesheet" type="text/css" href="styles.css">
    -->

  </head>
  
 <body>
    <h1>管理员登陆</h1>
    <!-- 准备交给path为/login的分派Action处理,里面的login函数处理登录请求 -->
    <form action="/essh/login.do?flag=login" method="post">
    <table>
        <tr><td>id:</td><td><input type="text" name="id"></td></tr>
        <tr><td>密码:</td><td><input type="password" name="password"></td></tr>
        <tr><td><input type="submit" value="登录"></td><td><input type="reset" value="重置"></td></tr>
    </table>
        
    </form>
  </body>
</html>

  1.2在index.jsp中,将首页面跳往此界面

<body>
    <jsp:forward page="/WEB-INF/login.jsp"></jsp:forward>
  </body>

 

2.建立编写struts中的action和form,配置struts-config.xml文件

  2.1建包com.myz.web.actions,在包下新建LoginAction

package com.myz.web.actions;

import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

import org.apache.struts.action.ActionForm;
import org.apache.struts.action.ActionForward;
import org.apache.struts.action.ActionMapping;
import org.apache.struts.actions.DispatchAction;

public class LoginAction extends DispatchAction {
    
    public ActionForward login(ActionMapping mapping, ActionForm form,
            HttpServletRequest request, HttpServletResponse response) throws Exception {
        // TODO Auto-generated method stub
        return super.execute(mapping, form, request, response);
    }
}

  2.2建包com.myz.web.forms

import org.apache.struts.action.ActionForm;

public class EmployeeForm extends ActionForm {
    //属性名称与login.jsp中的控件名称一样
    private Integer id;
    private String password;
    public Integer getId() {
        return id;
    }
    public void setId(Integer id) {
        this.id = id;
    }
    public String getPassword() {
        return password;
    }
    public void setPassword(String password) {
        this.password = password;
    }
}

  2.3在WEB-INF下新建并配置struts-config.xml

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE struts-config PUBLIC "-//Apache Software Foundation//DTD Struts Configuration 1.2//EN" "http://struts.apache.org/dtds/struts-config_1_2.dtd">
<struts-config>
    <form-beans>
        <form-bean name="employeeForm" type="com.myz.web.forms.EmployeeForm"></form-bean>
    </form-beans>
    <action-mappings>
        <action path="/login" parameter="flag" name="employeeForm" type="com.myz.web.actions.LoginAction">
            <forward name="ok" path="/WEB-INF/mainFrame.jsp"></forward>
            <forward name="err" path="/WEB-INF/login.jsp"></forward>
        </action>
    </action-mappings>
</struts-config>

  2.4依据配置信息,在WEB-INF下新建mainFrame.jsp

<%@ page language="java" import="java.util.*" pageEncoding="utf-8"%>
<%
String path = request.getContextPath();
String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";
%>

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
  <head>
    <base href="<%=basePath%>">
    
    <title>My JSP 'mainFrame.jsp' starting page</title>
    
    <meta http-equiv="pragma" content="no-cache">
    <meta http-equiv="cache-control" content="no-cache">
    <meta http-equiv="expires" content="0">    
    <meta http-equiv="keywords" content="keyword1,keyword2,keyword3">
    <meta http-equiv="description" content="This is my page">
    <!--
    <link rel="stylesheet" type="text/css" href="styles.css">
    -->

  </head>
  
  <body>
      <h2>欢迎登录</h2>
    <a href="#">添加员工</a><br/>
    <a href="#">显示员工</a><br/>
    <a href="#">删除员工</a><br/>
    <a href="#">修改员工</a><br/>
  </body>
</html>

  2.5对LoginAction中的login函数修改,使其能够对提交的信息进行简单处理

public class LoginAction extends DispatchAction {
    
    public ActionForward login(ActionMapping mapping, ActionForm form,
            HttpServletRequest request, HttpServletResponse response) throws Exception {
        // TODO Auto-generated method stub
        EmployeeForm employeeForm=(EmployeeForm) form;
        //简单验证,如果密码是123就通过
        if(employeeForm.getPassword().equals("123")){
            return mapping.findForward("ok");
        }else{
            return mapping.findForward("err");
        }
    }
}

  2.6在web.xml中配置ActionServlet总控制器

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" 
    xmlns="http://java.sun.com/xml/ns/javaee" 
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
    xsi:schemaLocation="http://java.sun.com/xml/ns/javaee 
    http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
    
    <servlet>
      <servlet-name>struts</servlet-name>
      <servlet-class>org.apache.struts.action.ActionServlet</servlet-class>
      <init-param>
          <param-name>config</param-name>
        <param-value>/WEB-INF/struts-config.xml</param-value>
      </init-param>
  </servlet>
  
      <servlet-mapping>
          <servlet-name>struts</servlet-name>
          <url-pattern>*.do</url-pattern>
      </servlet-mapping>
  <welcome-file-list>
    <welcome-file>index.jsp</welcome-file>
  </welcome-file-list>
</web-app>

 

3.测试,将项目发布到tomcat,浏览器中输入地址http://localhost:8080/essh

  3.1输入用户名和密码,输入密码为123则登录到mainFrame.jsp主页面

  3.2只要密码不为123,则返回登录界面,登录失败

 

posted @ 2018-02-09 15:23  菜鸡蔡文姬  阅读(137)  评论(0编辑  收藏  举报