一、ssh整合第一步,导包和建立applicationContext.xml
1.新建web项目essh,导入spring、struts、hibernate开发包,以及数据库的驱动包
1.1将对应jar包复制到WEB-INF的lib目录下,系统就会自动导入
2.在src目录下新建applicationContext.xml,编辑好文件头
<?xml version="1.0" encoding="utf-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:context="http://www.springframework.org/schema/context" xmlns:tx="http://www.springframework.org/schema/tx" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-2.5.xsd http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-2.5.xsd">
</beans>
3.测试applicationContext.xml是否能够使用
3.1新建包com.myz.test,在包下新建TestService类,作为一个javaBean用来测试
package com.myz.test; public class TestService { private String name; public String getName() { return name; } public void setName(String name) { this.name = name; } }
3.2在applicationContext.xml中配置TestService
<?xml version="1.0" encoding="utf-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:context="http://www.springframework.org/schema/context" xmlns:tx="http://www.springframework.org/schema/tx" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-2.5.xsd http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-2.5.xsd"> <bean name="testService" class="com.myz.test.TestService"> <property name="name" value="蔡文姬"></property> </bean> </beans>
3.3在包com.myz.test包下新建Test类,编辑如下代码
package com.myz.test; import org.springframework.context.ApplicationContext; import org.springframework.context.support.ClassPathXmlApplicationContext; public class Test { public static void main(String[] args) { ApplicationContext ac=new ClassPathXmlApplicationContext("applicationContext.xml"); TestService ts=(TestService) ac.getBean("testService"); System.out.println(ts.getName()); } }
3.4控制台输出“蔡文姬”,证明测试成功!