java数字加密算法

数字加密在项目中时常会遇到,如手机号,身份证号信息等,下面小白将自己手写的数字加密算法分享给大家,可在项目中直接运用.
加密规则,入参时传递一个字段时间戳 time:
* 1.以字母代替数字,0-9分别为["D","e","C","A","#","b","J","I","z","M"]
* 2.混淆字母为FxYNgq;
* 3.加密字符串等于初始数字加时间戳乘以数字密钥(5658116)再把数字结果转换成字母;
* 4.对于加密字符串长度小于总加密字符串长度(32)的随机插入混淆字母
例:
(15755141030 + 1544769549545)*5658116=8829629720137456700-->
再转换成字母
qFzzYFCMJYqCMgICDNxFeAqI#bJgIFDD;
package com.example.demo.t2;
import java.util.regex.Pattern;

/**
 * Created by ypf on 2018/12/14.
 */
public class Test {

    //数字秘钥
    private final static long SECRET_KEY = 5658116;
    //转换字符(0-9分别为["D","e","C","A","#","b","J","I","z","M"]
    private final static String CONVERT_KEY = "DeCA#bJIzM";
    //混淆字母
    private final static String CONFUSED_WORDS_KEY = "FxYNgq";
    //总加密字符串长度
    private final static int LEN_KEY = 32;
    
    /**
     *   数字加密算法
     **/
    public String encrypt(String str,long time){

        //数字校验
        if(!isNumber(str)){
            System.out.println(str + "不是数字");
            return null;
        }

        long number = Long.parseLong(str);
        long newNumber = (number + time) * SECRET_KEY;
        String[] numArr = String.valueOf(newNumber).split("");
        String[] initArr = CONVERT_KEY.split("");
        int len = numArr.length;
        StringBuffer buffer = new StringBuffer();

        //数字转字母
        for(int i = 0; i < len; i++){
            int inx = Integer.parseInt(numArr[i]);
            buffer.append(initArr[inx]);
        }

        //随机加入混淆字符
        String[] cwkArr = CONFUSED_WORDS_KEY.split("");
        if(len < LEN_KEY){
            int l = LEN_KEY - len;
            for(int i = 0; i < l; i++){
                int index = (int)(Math.random()*buffer.length());
                int inx = (int)(Math.random()*(CONFUSED_WORDS_KEY.length()));
                buffer.insert(index,cwkArr[inx]);
            }
        }
        String result = buffer.toString();
        System.out.println("加密字符串:" + result);
        return result;
    }

    /**
     * 解密算法
     * */
    public String decrypt(String str,long time){
        if(null == str || "".equals(str)){
            System.out.println("参数为空");
            return null;
        }
        int l = CONFUSED_WORDS_KEY.length();
        String[] cwkArr = CONFUSED_WORDS_KEY.split("");
        for(int i = 0; i < l; i++){
            str = str.replaceAll(cwkArr[i],"");
        }
        String[] initArr = str.split("");
        int len = initArr.length;
        StringBuffer result = new StringBuffer();
        for(int i = 0; i < len; i++ ){
            int k = CONVERT_KEY.indexOf(initArr[i]);
            if(k == -1){
                System.out.println("转化失败:" + str);
                return null;
            }
            result.append(k);
        }
        Long number;
        try {
            long total = Long.parseLong(result.toString());
            long sum = total/SECRET_KEY;
            number = sum - time;
            System.out.println("解密后数字:" + number);
        } catch (NumberFormatException e) {
            e.printStackTrace();
            return null;
        }
        return number.toString();
    }

    /**
     *   测试
     **/
    public static void main(String[] args) {
        long time = System.currentTimeMillis();
        System.out.println("time:" + time);
        Test t = new Test();
        String number = "15755141030";
        System.out.println(number);
        String result = t.encrypt(number,time);
        t.decrypt(result,time);
    }

    /**
     *  数字校验
     * */
    public static boolean isNumber(String value) {
        String pattern = "^[0-9]*[1-9][0-9]*$";
        boolean isMatch = Pattern.matches(pattern, value);
        return isMatch;
    }
}
运行结果如下:
Connected to the target VM, address: '127.0.0.1:62962', transport: 'socket'
time:1544769549545
15755141030
加密字符串:qFzzYFCMJYqCMgICDNxFeAqI#bJgIFDD
解密后数字:15755141030
Disconnected from the target VM, address: '127.0.0.1:62962', transport: 'socket'

Process finished with exit code 0

 总结:此加密算法虽然简单,但加密思想和加密原理值得学习,可以随意修改数字秘钥、转换字符、混淆字母、总加密字符串长度,并用于项目中。

posted @ 2018-12-14 15:33  细雨笑澄风  阅读(5619)  评论(0编辑  收藏  举报