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LeetCode 11 -- Container With Most Water

Given n non-negative integers a1a2, ..., an, where each represents a point at coordinate (iai). n vertical lines are drawn such that the two endpoints of line i is at (i,ai) and (i, 0). Find two lines, which together with x-axis forms a container, such that the container contains the most water.


简单方法就是暴力破解,不过肯定会超时。

仔细想想,可以使用双指针指向数组头尾解决。需要注意的就是短板问题,要想获取较大的容量,只能通过移动较小的指针,否则肯定变小。

 1 public class ContainerWithMostWater {
 2     public static int maxArea(int[] height){
 3         int maxarea = 0;
 4         int area = 0;
 5         int l = 0;
 6         int r = height.length - 1;
 7         while( l < r){
 8             area = min(height[l] , height[r]) * ( r - l);
 9             if ( area > maxarea)
10                 maxarea = area;
11             
12             if( height[l] < height[r])
13                 l++;
14             else
15                 r--;
16         }
17         return maxarea;
18     }
19     
20     static int min( int a,int b){
21         return a>b ? b : a;
22     }
23 }

 

posted on 2015-07-28 17:10  myshuangwaiwai  阅读(152)  评论(0编辑  收藏  举报