摘要: SELECT company.id,company.zz,snap.xydm,snap."companyName", p.xm fr from ( SELECT a.id,string_agg( case when d.zzlx = 1 then '路基路面' when d.zzlx = 2 the 阅读全文
posted @ 2022-07-21 09:52 懂得归零 阅读(1542) 评论(0) 推荐(0) 编辑