pgsql或取最新的一条数据

SELECT company.id,company.zz,snap.xydm,snap."companyName", p.xm fr from (
  SELECT a.id,string_agg(
  case
  when d.zzlx = 1 then '路基路面'
  when d.zzlx = 2 then '桥梁'
  when d.zzlx = 3 then '隧道'
  when d.zzlx = 4 then '交通安全设施' end
  ||
  case
  when d.zzdj = 1 then '甲级'
  when d.zzdj = 2 then '乙级'
  else '' end , ',') as zz
  from company_info a
  left join company_info_snapshot b on a.id = b.company_id
  left join company_aptitude_r c on c.snapshot_id = b.id
  left join aptitude d on c.aptitude_id = d.id
  where d.id is not null and a.del_flag = 2 and d.del_flag = 2 and b.del_flag = 2 and zt = 2
  and concat(a.name,a.xydm) like concat('%','','%')
  GROUP BY a.id
) company
left join (
  SELECT company_id,(array_agg(id order by create_time desc ))[1] snapshot_id,
  (array_agg(name order by create_time desc ))[1] as "companyName",
  (array_agg(xydm order by create_time desc ))[1] xydm,
  (array_agg(fddbr order by create_time desc ))[1] fddbr
  from company_info_snapshot
  GROUP BY company_id
) snap on snap.company_id = company.id
left join personnel p on p.id = snap.fddbr

posted @ 2022-07-21 09:52  懂得归零  阅读(1528)  评论(0编辑  收藏  举报