静态加载问题
阿里笔试题
连接:http://blog.csdn.net/geekdonie/article/details/12260599
public class Test { public static int k = 0; public static Test t1 = new Test("t1"); public static Test t2 = new Test("t2"); public static int i = print("i"); public static int n = 99; private int a = 0; public int j = print("j"); { print("构造块"); } static { print("静态块"); } public Test(String str) { System.out.println((++k) + ":" + str + " i=" + i + " n=" + n); ++i; ++n; } public static int print(String str) { System.out.println((++k) + ":" + str + " i=" + i + " n=" + n); ++n; return ++i; } public static void main(String args[]) { Test t = new Test("init"); } }
结果输出:
1:j i=0 n=0 2:构造块 i=1 n=1 3:t1 i=2 n=2 4:j i=3 n=3 5:构造块 i=4 n=4 6:t2 i=5 n=5 7:i i=6 n=6 8:静态块 i=7 n=99 9:j i=8 n=100 10:构造块 i=9 n=101 11:init i=10 n=102
笔试题2:
public class Test { static { int x = 5; } static int x, y; public static void main(String[] args) { x--; myMethod(); System.out.println(x + y++ + x); } public static void myMethod(){ y = x++ + ++x; } }
输出:2