2016 China Collegiate Programming Contest Final
Problem A. The Third Cup is Free 签到
1 #include <bits/stdc++.h> 2 using namespace std; 3 const int inf=0x3f3f3f3f; 4 const int maxn=100005; 5 int T,n,a[maxn],b[4],tot; 6 int main() 7 { 8 scanf("%d",&T); 9 for (int cas=1;cas<=T;++cas) { 10 scanf("%d",&n); 11 tot=0; 12 for (int i=0;i<n;++i) { 13 scanf("%d",&a[i]); 14 tot+=a[i]; 15 } 16 sort(a,a+n); 17 for (int i=n-1;i>=0;i-=3) 18 if (i>=2) 19 tot-=a[i-2]; 20 printf("Case #%d: %d\n",cas,tot); 21 } 22 return 0; 23 }
Problem B. Wash
1 #include <cstdio> 2 #include <algorithm> 3 #include <queue> 4 using namespace std; 5 typedef pair<long long,long long> pll; 6 const int maxn=100005; 7 const int maxl=1000005; 8 const long long inf=0x3f3f3f3f3f3f3f3f; 9 int T,n,m1,m2; 10 long long t1[maxn],t2[maxn],res1[maxl],res2[maxl]; 11 priority_queue<pll,vector<pll>,greater<pll> > que; 12 int main() 13 { 14 scanf("%d",&T); 15 for (int cas=1;cas<=T;++cas) { 16 scanf("%d%d%d",&n,&m1,&m2); 17 for (int i=0;i<m1;++i) { 18 scanf("%I64d",&t1[i]); 19 que.push(pll(t1[i],t1[i])); 20 } 21 for (int i=1;i<=n;++i) { 22 res1[i]=que.top().first; 23 long long id=que.top().second; 24 que.pop(); 25 que.push(pll(res1[i]+id,id)); 26 } 27 while (!que.empty()) 28 que.pop(); 29 for (int i=0;i<m2;++i) { 30 scanf("%I64d",&t2[i]); 31 que.push(pll(t2[i],t2[i])); 32 } 33 for (int i=1;i<=n;++i) { 34 res2[i]=que.top().first; 35 long long id=que.top().second; 36 que.pop(); 37 que.push(pll(res2[i]+id,id)); 38 } 39 while (!que.empty()) 40 que.pop(); 41 long long res=0; 42 for (int i=1;i<=n;++i) 43 res=max(res,res1[i]+res2[n-i+1]); 44 printf("Case #%d: %I64d\n",cas,res); 45 } 46 return 0; 47 }
Problem G. Pandaland 删边暴力最短路，在暴力过程中分支界限法剪枝。
1 #include <bits/stdc++.h> 2 #define REP(i,x,y) for(int i=x;i<(y);i++) 3 const long long mod = 1e9+7; 4 const double ex = 1e-10; 5 #define inf 0x3f3f3f3f 6 #define maxn 8010 7 using namespace std; 8 typedef pair<int,int>pii; 9 int n,m; 10 map<pii,int>ma; 11 struct edge{ 12 int v,to,cost,flag; 13 edge(){} 14 edge(int v,int _to,int _cost,int flag=0):v(v),to(_to),cost(_cost),flag(flag){} 15 }; 16 int tmp = inf; 17 vector<edge>edges; 18 vector<int>e[maxn]; 19 inline void add_edge(int u,int v,int w) { 20 edges.push_back(edge(u,v,w,0)); 21 edges.push_back(edge(v,u,w,0)); 22 int cnt=edges.size(); 23 e[u].push_back(cnt-2); 24 e[v].push_back(cnt-1); 25 } 26 int dis[maxn],vis[maxn]; 27 void spfa(int st) { 28 memset(dis,inf,sizeof(int)*(n+5));memset(vis,0,sizeof(int)*(n+5)); 29 dis[st]=0;vis[st]=1; 30 priority_queue<int>que; 31 que.push(st); 32 while(!que.empty()){ 33 int now=que.top();que.pop(); 34 for(int i=0;i<e[now].size();i++){ 35 int next=edges[e[now][i]].to;int len=edges[e[now][i]].cost; 36 if(edges[e[now][i]].flag==1) continue; 37 if(dis[next]>dis[now]+len){ 38 dis[next]=dis[now]+len; 39 if(!vis[next]&&dis[next] <= tmp){ 40 que.push(next); 41 vis[next]=1; 42 } 43 } 44 } 45 vis[now]=0; 46 } 47 } 48 int main() 49 { 50 int T,cas=1;scanf("%d",&T); 51 while(T--) { 52 scanf("%d",&m); 53 n=0; 54 edges.clear();ma.clear(); 55 for(int i=0;i<maxn;i++) e[i].clear(); 56 REP(i,1,m+1) { 57 int u,v,x,y,w;scanf("%d %d %d %d %d",&u,&v,&x,&y,&w); 58 pii now=make_pair(u,v),now2=make_pair(x,y); 59 if(ma.count(now)==0) ma[now]=++n; 60 if(ma.count(now2)==0) ma[now2]=++n; 61 // cout<<ma[now]<<" "<<m 62 add_edge(ma[now],ma[now2],w); 63 // add_edge(ma[now2],ma[now],w); 64 } 65 int ans=inf+(inf/2); 66 for(int i=0;i<edges.size();i++) { 67 if(i%2) continue; 68 edges[i].flag=1; 69 edges[i^1].flag=1; 70 tmp = ans - edges[i].cost; 71 spfa(edges[i].v); 72 // REP(i,1,n+1) cout<<i<<" "<<dis[i]<<endl; 73 ans=min(ans,edges[i].cost+dis[edges[i].to]); 74 edges[i].flag=0; 75 edges[i^1].flag=0; 76 } 77 if (ans >= inf) ans = 0; 78 printf("Case #%d: %d\n",cas++,ans); 79 } 80 return 0; 81 }
Problem H. Engineer Assignment 状压DP
1 #include <bits/stdc++.h> 2 using namespace std; 3 int T,n,m,p[15][4],c[15][3],dp[11][1024]; 4 bool ok[11][1024]; 5 inline bool check(int x,int st) { 6 for (int k=1;k<=p[x][0];++k) { 7 bool flag=false; 8 for (int i=0;i<m;++i) { 9 if ((st>>i)&1) 10 for (int j=1;j<=c[i][0];++j) 11 if (p[x][k]==c[i][j]) { 12 flag=true; 13 break; 14 } 15 if (flag) 16 break; 17 } 18 if (!flag) 19 return false; 20 } 21 return true; 22 } 23 int main() 24 { 25 scanf("%d",&T); 26 for (int cas=1;cas<=T;++cas) { 27 scanf("%d%d",&n,&m); 28 for (int i=1;i<=n;++i) { 29 scanf("%d",&p[i][0]); 30 for (int j=1;j<=p[i][0];++j) 31 scanf("%d",&p[i][j]); 32 } 33 for (int i=0;i<m;++i) { 34 scanf("%d",&c[i][0]); 35 for (int j=1;j<=c[i][0];++j) 36 scanf("%d",&c[i][j]); 37 } 38 int s=1<<m; 39 for (int i=1;i<=n;++i) 40 for (int j=0;j<s;++j) { 41 ok[i][j]=check(i,j); 42 dp[i][j]=0; 43 } 44 for (int i=1;i<=n;++i) { 45 for (int j=0;j<s;++j) 46 dp[i][j]=dp[i-1][j]; 47 for (int j=0;j<s;++j) if (ok[i][j]) 48 for (int k=0;k<s;++k) 49 if ((j&k)==0) 50 dp[i][j^k]=max(dp[i][j^k],dp[i-1][k]+1); 51 } 52 int res=0; 53 for (int i=1;i<=n;++i) 54 for (int j=0;j<s;++j) 55 res=max(res,dp[i][j]); 56 printf("Case #%d: %d\n",cas,res); 57 } 58 return 0; 59 }
Problem I. Mr. Panda and Crystal 类似于SPFA一样DP，之后裸的完全背包
1 #include <bits/stdc++.h> 2 const long long mod = 1e9+7; 3 const double ex = 1e-10; 4 #define inf 0x3f3f3f3f 5 using namespace std; 6 int cost[300]; 7 int vv[300]; 8 int vis[300]; 9 struct node{ 10 int to,id,nex; 11 }E[40044]; 12 int head[300]; 13 int cnt = 0; 14 void addedge(int x,int y,int id){ 15 E[cnt] = node{y,id,head[x]}; 16 head[x] = cnt++; 17 } 18 int num[300]; 19 typedef pair<int,int> pii; 20 int dp[10001]; 21 vector <pii> fun[300][300]; 22 int main() 23 { 24 int T; 25 scanf("%d",&T); 26 int cas = 1; 27 while (T--){ 28 int n,m,k; 29 scanf("%d%d%d",&m,&n,&k); 30 memset(head,-1,sizeof(head)); 31 memset(num,0,sizeof(num)); 32 for (int i = 1 ; i<300; i++) 33 for (int j = 0; j<300;j++){ 34 fun[i][j].clear(); 35 } 36 cnt = 0; 37 queue<int> Q; 38 for (int i = 1; i<=n;i++){ 39 int t; 40 scanf("%d",&t); 41 if ( t == 1 ){ 42 int d; 43 scanf("%d",&d); 44 cost[i] = d; 45 Q.push(i); 46 vis[i] = 1; 47 } 48 else cost[i] = inf; 49 int c; 50 scanf("%d",&c); 51 vv[i] = c; 52 } 53 for (int i = 1; i <= k ; i++){ 54 int x,y; 55 scanf("%d%d",&x,&y); 56 num[x]++; 57 for (int j = 1; j <= y ; j++){ 58 int u,v; 59 scanf("%d%d",&u,&v); 60 addedge(u,x,num[x]); 61 fun[x][num[x]].push_back(make_pair(u,v)); 62 } 63 } 64 65 while (!Q.empty()){ 66 int now = Q.front(); 67 Q.pop(); 68 for (int i = head[now] ; i!=-1 ; i=E[i].nex){ 69 int to = E[i].to; 70 int id = E[i].id; 71 int sum = 0; 72 for (int j = 0 ; j<fun[to][id].size() ; j++){ 73 if (cost[fun[to][id][j].first]==inf) {sum = inf;break;} 74 sum += cost[fun[to][id][j].first] * fun[to][id][j].second; 75 if (sum > inf ) break; 76 } 77 if (sum < cost[to]){ 78 cost[to] = sum; 79 if (!vis[to]){ 80 Q.push(to); 81 vis[to] = 1; 82 } 83 } 84 } 85 vis[now] = 0; 86 } 87 memset(dp,0,sizeof(dp)); 88 for (int i = 1; i<=n; i++){ 89 for (int j = cost[i]; j<=m; j++){ 90 dp[j] = (max(dp[j - cost[i]] + vv[i],dp[j])); 91 } 92 } 93 int ans = 0; 94 for (int i = 1 ; i<=m ;i++){ 95 ans = max(ans,dp[i]); 96 } 97 printf("Case #%d: %d\n",cas++,ans); 98 } 99 return 0; 100 }
Problem J. Worried School 目测岛娘嘲讽黄金熊
1 #include <bits/stdc++.h> 2 const long long mod = 1e9+7; 3 const double ex = 1e-10; 4 #define inf 0x3f3f3f3f 5 using namespace std; 6 string S[6][25]; 7 map<string,int> M; 8 int main() 9 { 10 int T; 11 int cas = 0; 12 scanf("%d",&T); 13 while (T--){ 14 int n; 15 scanf("%d",&n); 16 string SS; 17 cin >> SS; 18 for (int i = 0 ;i<=5 ;i++) 19 { 20 for (int j = 0 ; j<20 ;j++) 21 cin >> S[i][j]; 22 } 23 int i = 0; 24 for (i = 0 ; i<=n; i++){ 25 M.clear(); 26 int cnt = 0; 27 for (int j = 1; j <= n-i ;j++){ 28 while (M[S[cnt%5][cnt/5]]!=0){ 29 cnt++; 30 } 31 //cout << S[cnt%5][cnt/5] << endl; 32 M[S[cnt%5][cnt/5]]++; 33 } 34 cnt = 0; 35 for (int j = 1; j<=i ;j++){ 36 while (M[S[5][cnt]]!=0){ 37 cnt++; 38 } 39 //cout << S[5][cnt] << endl; 40 M[S[5][cnt]]++; 41 } 42 if ( M[SS] == 0 ) break; 43 } 44 printf("Case #%d: ",++cas); 45 if (i>n) { 46 printf("ADVANCED!\n"); 47 } 48 else { 49 printf("%d\n",i); 50 } 51 } 52 return 0; 53 }
Problem L. Daylight Saving Time 时间模拟
1 #include <bits/stdc++.h> 2 #define maxn 100010 3 #define inf 0x3f3f3f3f 4 #define REP(i,x,y) for(int i=x;i<(y);i++) 5 #define RREP(i,x,y) for(int i=x;i>(y);i--) 6 using namespace std; 7 typedef long long ll; 8 typedef pair<int,int> pii; 9 inline int check(int month,int flag) { 10 if(flag==1&&month==2) return 29; 11 else if(flag==0&&month==2) return 28; 12 if(month==1||month==3||month==5||month==7||month==8||month==10||month==12) return 31; 13 else return 30; 14 } 15 int main() 16 { 17 int T;scanf("%d",&T);int cas=1; 18 while(T--) { 19 int year,month,day,hour,minute,second,flag=0; 20 scanf("%d-%d-%d",&year,&month,&day); 21 scanf("%d:%d:%d",&hour,&minute,&second); 22 printf("Case #%d: ",cas++); 23 if((year%4==0&&year%100!=0)||(year%400==0)) flag=1; 24 // int limit=check(month,flag); 25 if(month>3&&month<11) {puts("PDT");continue;} 26 else if(month<3&&month>11) {puts("PST");continue;} 27 if(month==1||month==2) { 28 year--; 29 if(month==1) month=13; 30 else month=14; 31 } 32 int c=year/100;int y=year%100; 33 if(month==3) { 34 int tmp=0,cnt=0; 35 for(int i=1;i<=31;i++) { 36 int w=y+y/4+c/4-2*c+26*(month+1)/10+i-1; 37 if((w%7+7)%7==0) cnt++; 38 if(cnt==2) {tmp=i;break;} 39 } 40 // cout<<tmp<<endl; 41 if(tmp<day) puts("PST"); 42 else if(tmp>day) puts("PDT"); 43 else { 44 if(hour==2) puts("Neither"); 45 else if(hour>2) puts("PDT"); 46 else puts("PST"); 47 } 48 } 49 if(month==11) { 50 int tmp=0,cnt=0; 51 for(int i=1;i<=31;i++) { 52 int w=y+y/4+c/4-2*c+26*(month+1)/10+i-1; 53 if((w%7+7)%7==0) cnt++; 54 if(cnt==1) {tmp=i;break;} 55 } 56 if(tmp<day) puts("PDT"); 57 else if(tmp>day) puts("PST"); 58 else { 59 if(hour==1) puts("Both"); 60 else if(hour<1) puts("PDT"); 61 else puts("PST"); 62 } 63 } 64 } 65 }
