摘要：
import re m=re.match("abc","abcdef") m=re.match("[0-9]","75ab6def") 7 从头匹配 m=re.match("[0-9][0-9]","75ab6def") 75 m=re.match("[0-9]{0,10}","755625ab6d 阅读全文
摘要：
data=[[col for col in rang(4)] for row in rang(4)] for row in data: print(row) print(" ") for r_index, row in enumerate(data): for c_index in range (r 阅读全文
摘要：
def binary_search(data_source,find_n): mind=int(len(data_source)/2) if len(data_source)>=1: if data_source[mid]>find_n: print("data in left of [%s]"%s 阅读全文