多个数组对象合并去重

一个数组对象去重

 1 var songs = [
 2  {name:"羽根",artist:"air"}, 
 3 {name:"羽根",artist:"air"}, 
 4 {name:"晴天",artist:"周杰伦"}, 
 5 {name:"晴天",artist:"周杰伦"}, 
 6 {artist:"周杰伦",name:"晴天"} 
 7 ];
 8 
 9 function unique(songs){ 
10     let result = {}; 
11     let finalResult=[]; 
12     for(let i=0;i<songs.length;i++){ 
13      result[songs[i].name]=songs[i];//因为songs[i].name不能重复,达到去重效果,且这里必须知晓"name"或是其他键名
14  } 
15  //console.log(result);{"羽根":{name:"羽根",artist:"air"},"晴天":{name:"晴天",artist:"周杰伦"}} //现在result内部都是不重复的对象了，只需要将其键值取出来转为数组即可
16     for(item in result){ 
17      finalResult.push(result[item]); 
18     } 
19 //console.log(finalResult);[{name:"羽根",artist:"air"},{name:"晴天",artist:"周杰伦"}]
20  return finalResult; 
21 } 
22 console.log(unique(songs));

 

多个数组对象去重

var songs = [
 {name:"羽根",artist:"air"}, 
{name:"晴天",artist:"周杰伦"}, 
{artist:"周杰伦",name:"晴天"} 
];

var arr = [
{name:"羽根",artist:"air"}, 
{name:"晴天",artist:"周杰伦"}, 
]

for (let i = 0; i < arr.length; i++) {
    songs.push(arr[i])
}

console.log(songs);


function unique(songs){ 
    let result = {}; 
    let finalResult=[]; 
    for(let i=0;i<songs.length;i++){ 
     result[songs[i].name]=songs[i];//因为songs[i].name不能重复,达到去重效果,且这里必须知晓"name"或是其他键名
 } 
 //console.log(result);{"羽根":{name:"羽根",artist:"air"},"晴天":{name:"晴天",artist:"周杰伦"}} //现在result内部都是不重复的对象了，只需要将其键值取出来转为数组即可
    for(item in result){ 
     finalResult.push(result[item]); 
    } 
//console.log(finalResult);[{name:"羽根",artist:"air"},{name:"晴天",artist:"周杰伦"}]
 return finalResult; 
} 
console.log(unique(songs));

 

posted @ 2018-06-28 13:47  秀&莹&锐  阅读(6211)  评论(0)  编辑  收藏  举报