根据固定的时间,获取到当前时间的月份的时间数组

比如从2018年10月获取到当前的时间的月份数组

/**
 * 从固定的年月获取到当前时间的数组  倒序
 * @param {*} start_year 固定的年份    number  必传
 * @param {*} start_mon 固定的月份    number   必传
 * @param {*} type 需要'-'或不需要''  string   必传
 */
export function GetPreMonthDay (start_year, start_mon, type) {
  //创建现在的时间
  let data = new Date();
  //获取年
  let year = data.getFullYear();
  //获取月
  let mon = data.getMonth() + 1;
  let arry = [];
  let num = 13;
  let list = [];
  let mon1 = mon,mon2 = mon, year1 = year, year2;
  for (let i = 0; i < (num - start_mon); i++) {
    mon1 = i == 0 ? start_mon : parseInt(mon1) + 1;
    if (parseInt(mon1) <= 0) {
      start_year = parseInt(start_year) - 1;
      mon1 = parseInt(mon1) + 12;
    } else if (parseInt(mon1) > 12) {
      start_year = parseInt(start_year) + 1;
      mon1 = parseInt(mon1) - 12;
    }
    if (parseInt(mon1) < 10) {
      mon1 = "0" + mon1;
    }
    arry.unshift({
      name: start_year + "年" + mon1 + '月',
      value: start_year + type + mon1,
    });
  }
  if (year1 > start_year) {
    for (let y = 0; y < (year1 - start_year); y++) {
      year2 = y == 0 ? start_year + 1 : year2 + 1;
      for (let i = 0; i < 12; i++) {
        mon2 = i == 0 ? 1 : parseInt(mon2) + 1;
        if (year2 == year && mon2 > mon) {
          break;
        }
        if (parseInt(mon2) <= 0) {
          year2 = parseInt(year2) - 1;
          mon2 = parseInt(mon2) + 12;
        } else if (parseInt(mon2) > 12) {
          year2 = parseInt(year2) + 1;
          mon2 = parseInt(mon2) - 12;
        }
        if (parseInt(mon2) < 10) {
          mon2 = "0" + mon2;
        }
        list.unshift({
          name: year2 + "年" + mon2 + '月',
          value: year2 + type + mon2,
        })
      }
    }
  }
  let time = list.concat(arry);
  return time;
}

 

这个是倒序的,如果需要正序,就把unshift更改为push

posted @ 2019-01-24 15:54  秀&莹&锐  阅读(251)  评论(0编辑  收藏  举报