六种排序
如题。
#include <stdio.h> #include <string.h> #include <stdlib.h> #include <math.h> #include <ctype.h> #include <time.h>//我要搞事 (`・ω・´) #define max(A, B) ((A > B) ? A : B) #define min(A, B) ((A < B) ? A : B) void swap(int arr[], int i, int j); void QuickSort(int arr[], int left, int right); void ShellSort(int arr[], int left, int right); void InsertSort(int arr[], int left, int right); void BucketSort(int arr[], int left, int right); void SelectSort(int arr[], int left, int right); void Merge(int arr[], int left, int mid, int right); void MergeSort(int arr[], int left, int right); int main() { int n; int *arr; int i; scanf("%d", &n); arr = (int*)malloc(sizeof(int) * (n + 1)); for (i = 1; i <= n; i++) scanf("%d", arr + i); /*想测试人品吗?srand((unsigned)time(0)); int temp = rand() % 6; //骚一波 ≖‿≖✧ ps:拼人品,有可能过不了 switch (temp) { case 0: QuickSort(arr, 1, n); break; case 1: ShellSort(arr, 1, n); break; case 2: InsertSort(arr, 1, n); break; case 3: BucketSort(arr, 1, n); break; case 4: SelectSort(arr, 1, n); break; case 5: MergeSort(arr, 1, n); break; default: printf("error: rand()? or mod Σ( ° △ °|||)︴\n"); break; }*/ MergeSort(arr, 1, n); for (i = 1; i <= n; i++) printf("%d ", arr[i]); return 0; } void swap(int arr[], int i, int j) { int temp; temp = arr[i]; arr[i] = arr[j]; arr[j] = temp; } void QuickSort(int arr[], int left, int right) { int i, pivot; if (left >= right) return; pivot = left; swap(arr, left, (left + right) / 2); for (i = left + 1; i <= right; i++) //单边搜索,可以该为双向搜索(据说快点( ° ▽、° )) if (arr[i] < arr[left]) swap(arr, i, ++pivot); swap(arr, left, pivot); QuickSort(arr, left, pivot - 1); QuickSort(arr, pivot + 1, right); } void ShellSort(int arr[], int left, int right) { int gap, i, j; //ShellSort因为我只写过0——n-1的(最标准的),可能有点小bug(不过应该没错吧 (*´Д`*) ) for (gap = (left + right) / 2; gap > 0; gap /= 2) for (i = gap; i <= right; i++) for (j = i - gap; j > 0 && arr[j] > arr[j + gap]; j -= gap) swap(arr, j, j + gap); } void InsertSort(int arr[], int left, int right) { int i, v; for (i = left; i <= right; i++) { v = arr[i]; int l = left, r = i; int j; while (l < r) {//在l与r之间插入排序,可以理解为解决子问题1→2→...→n int mid = (l + r) / 2; if (arr[mid] <= v) l = mid + 1; else r = mid; } for (j = i - 1; l <= j; j--) arr[j + 1] = arr[j]; arr[l] = v; } } void BucketSort(int arr[], int left, int right) { int i, v; static int cnt[123456] = { 0 }; for (i = left, v = 0; i <= right; i++) { v = max(v, arr[i]);//部分优化:统计最大值,不用遍历所有桶,但空间仍是个问题╮(╯▽╰)╭ cnt[arr[i]]++; } v++; while (v-- > 0) while (cnt[v]-- > 0) arr[--i] = v; } void SelectSort(int arr[], int left, int right) { int i, j, k; for (i = left; i <= right; i++) { for (j = k = i; j <= right; j++) //可以理解为对k进行选择,将k的指向第i-left小的 if (arr[j] < arr[k]) k = j; if (i < k) swap(arr, i, k); } } void Merge(int arr[], int left, int mid, int right) { //merge arr[L,M](sorted) and arr(M,R](sorted) into arr[L,R] static int p = 1, que[123456] = { 0 }; int pl = left, pr = mid; int ql = mid + 1, qr = right; while (pl <= pr || ql <= qr) { if ((ql > qr) || (pl <= pr && arr[pl] <= arr[ql])) //有点麻烦的判断,要考虑arr已提取完的情况 que[p++] = arr[pl++]; else que[p++] = arr[ql++]; } while (left <= right) arr[right--] = que[--p]; } void MergeSort(int arr[], int left, int right) { if (left >= right) return; int mid = (left + right) / 2; MergeSort(arr, left, mid); MergeSort(arr, mid + 1, right); Merge(arr, left, mid, right);//二分递归 }