python 多进程交互

from multiprocessing import Process, Queue

class Engine:
    def __init__(self):
        self.info = "Engine Info"
        self.order_queue = Queue()  # 创建一个用于接收订单的队列
        self.orders = []

    def get_info(self):
        return self.info

    def process_orders(self):
        while True:
            order_info = self.order_queue.get()
            if not order_info:  # 如果收到空数据,则退出循环
                break
            strategy_id, order = order_info
            self.orders.append((strategy_id, order))
            print(f"Engine: Order {order} received from Strategy #{strategy_id}. (Order processed)")

class Strategy(Process):
    def __init__(self, engine, queue):
        super().__init__()
        self.engine = engine
        self.queue = queue

    def run(self):
        while True:
            data = self.queue.get()
            if not data:  # 如果数据为空(或者其他退出条件),则退出循环
                break

            self.on_data(data)

    def on_data(self, data):
        info = self.engine.get_info()
        print(f"Strategy: Received data {data}, and info is {info}.")
        
        # 假设生成订单
        order = f"Order based on {data}"
        self.engine.order_queue.put((self.pid, order))  # 将订单信息放入订单队列

if __name__ == "__main__":
    engine = Engine()

    # 创建并保存策略子进程及其各自的队列
    queues = [Queue() for _ in range(3)]
    strategies = [Strategy(engine, queue) for queue in queues]

    for i in range(5):  # 示例推送5次数据
        for queue in queues:
            queue.put(f"Data_{i}")

    # 发送一个空数据到每个策略进程的队列中以结束它们
    for queue in queues:
        queue.put(None)

    # 启动一个单独的进程来处理订单
    order_processor = Process(target=engine.process_orders)
    order_processor.start()

    for strategy in strategies:
        strategy.start()

    for strategy in strategies:
        strategy.join()

    # 等待订单处理器完成所有订单处理
    order_processor.join()

    print("All strategies and order processor finished.")
    print("Orders received by Engine:", engine.orders)
posted @ 2024-02-21 16:56  MasonLee  阅读(10)  评论(0编辑  收藏  举报