1 //实验五任务三
2 #include <iostream>
3 #include<string>
4 #include <cmath>
5 using namespace std;
6 class vector_N
7 {
8 private:
9 int n;
10 int* p;
11 public:
12 vector_N();
13 vector_N(vector_N &B);
14 bool check(vector_N B);
15 int show_N();
16 friend istream& operator>>(istream& input, vector_N &B);
17 friend ostream& operator<<(ostream& output, vector_N &B);
18 friend int neiji(vector_N A, vector_N B);
19 vector_N operator+(vector_N B);
20 vector_N operator-(vector_N B);
21 vector_N operator*(int a);
22 int operator[](int B);
23 };
24
25 istream& operator>>(istream& input, vector_N &B)
26 {
27 cout << "请输入维数" << endl;
28 input >> B.n;
29 if (B.n <= 0)
30 {
31 cout << "Error Length!" << endl;
32 exit(0);//退出程序
33 }
34 else
35 {
36 B.p = new int[B.n];//动态数组
37 cout << "请分别输入各个坐标" << endl;
38 for (int i = 0; i < B.n; i++)
39 {
40 input >> B.p[i];
41 }
42 }
43 return input;
44 }
45 ostream& operator<<(ostream& output, vector_N &B)
46 {
47 for (int i = 0; i < B.n; i++)
48 {
49 if (i == 0)
50 {
51 output << "(";
52 }
53 cout << B.p[i];
54 if (i != B.n - 1)
55 {
56 output << ",";
57 }
58 else
59 {
60 output << ")" << endl;
61 }
62 }
63 return output;
64 }
65 int neiji(vector_N A, vector_N B)
66 {
67 int sum = 0;
68 if (A.n == B.n)
69 {
70 vector_N C(A);
71 for (int i = 0; i < A.n; i++)
72 {
73 C.p[i] = A.p[i] * B.p[i];
74 sum+=C.p[i];
75 }
76 return sum;
77 }
78 else
79 {
80 cout << "error" << endl;
81 }
82 }
83 vector_N::vector_N()
84 {
85 n = 0;
86 p = NULL;
87 }
88 vector_N::vector_N(vector_N &B)
89 {
90 n = B.n;
91 p = new int[B.n];
92 for (int i = 0; i < B.n; i++)
93 {
94 p[i] = B.p[i];
95 }
96 }
97 bool vector_N::check(vector_N B)
98 {
99 if (n == B.n) return true;
100 else
101 {
102 cout << "Mismatch Length!" << endl;
103 return false;
104 }
105 }
106 int vector_N::show_N()
107 {
108 return n;
109 }
110 vector_N vector_N::operator + (vector_N B)
111 {
112 vector_N A(B);
113 if (check(B))
114 {
115 for (int i = 0; i < n; i++)
116 {
117 A.p[i] = p[i] + B.p[i];
118 }
119 return A;
120 }
121 else
122 {
123 exit(0);
124 }
125 }
126 vector_N vector_N::operator - (vector_N B)
127 {
128 vector_N A(B);
129 cout << B;
130 if (check(B))
131 {
132 for (int i = 0; i < n; i++)
133 {
134 A.p[i] = p[i] - B.p[i];
135 }
136 return A;
137 }
138 else
139 {
140 exit(0);
141 }
142 }
143 vector_N vector_N:: operator*(int a)
144 {
145 for (int i = 0; i < n; i++)
146 {
147 this->p[i] = this->p[i] * a;
148 }
149 return *this;
150 }
151 /////////////////////////////////////////////
152 int vector_N::operator[](int y)
153 {
154 if (y>=0&&y<this->n)
155 {
156 int num = this->p[y];
157 return num;
158 }
159
160 else
161 {
162 cout << "Error Index" << endl;
163 }
164 }
165 int main()
166 {
167 int x,y;
168 vector_N a, b;
169 cin >> a;
170 cin >> b;
171 cout<<"数乘运算乘数："<<endl;
172 cin>>x;
173 cout<<"a中对应下标："<<endl;
174 cin>>y;
175 cout << "a+b=" << a + b;
176 cout << "a-b=" << a - b;
177 cout << "a*b=" << neiji(a,b)<<endl;
178 cout << "a*x = " << a.operator*(x);
179 cout << "a的y下标对应值："<<b.operator[](y)<<endl;
180 return 0;
181 }
