摘要: select id,cnt,sum(cnt) over w as sum_cntfrom( select 'a' as id, 1 as cnt union all select 'a' as id, 9 as cnt union all select 'a' as id, 4 as cnt uni 阅读全文
posted @ 2021-09-02 15:07 muyue123 阅读(88) 评论(0) 推荐(0) 编辑