Mysql异常解决
把group by字段group_id
使用函数any_value
把报错的字段name
//原代码 select name, group_id from game group by group_id
报错信息:
Expression #1 of SELECT list is not in GROUP BY clause and contains nonaggregated column 'game.name' which is not functionally dependent on columns in GROUP BY clause; this is incompatible with sql_mode=only_full_group_by
解决:
select any_value(name), group_id from game group by group_id
sql_mode=ONLY_FULL_GROUP_BY,STRICT_TRANS_TABLES,NO_ZERO_IN_DATE,NO_ZERO_DATE,ERROR_FOR_DIVISION_BY_ZERO,NO_AUTO_CREATE_USER,NO_ENGINE_SUBSTITUTION
命令行打开mysql.cnf,可以用whereis查找sudo vim /etc/mysql/conf.d/mysql.cnf
[mysqld]
sql_mode=STRICT_TRANS_TABLES,NO_ZERO_IN_DATE,NO_ZERO_DATE,ERROR_FOR_DIVISION_BY_ZERO,NO_AUTO_CREATE_USER,NO_ENGINE_SUBSTITUTION
打开navcat,
select @@global.sql_mode
set @@global.sql_mode ="STRICT_TRANS_TABLES,NO_ZERO_IN_DATE,NO_ZERO_DATE,ERROR_FOR_DIVISION_BY_ZERO,NO_AUTO_CREATE_USER,NO_ENGINE_SUBSTITUTION";
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