post方法名及参数为:(具体方法可参考https://www.cnblogs.com/mufengforward/p/10510337.html)

  public static String doPost(String httpUrl, String param) {   ...   }

如果方法参数param是要求以json字符串的形式传递则:

  1. 如果是JSONObject对象转字符串则:String result = HttpUtil.doPost(URL, json.toJsonString());

  2. Map转字符串则需采用:String result = HttpUtil.doPost(URL, JSON.toJSONString(map));

  注:使用map.toString() 时会出现参数解析不到的问题

  因为:json.toJsonString()转换后为:{"name":"ceshi","password":"123456"}

     map.toString()转换后为:{password=123456, name=ceshi}

  对比可知,参数不一致;

 

测试如下:

  public static void main(String[] args) {
        Map map = new HashMap<>();
        map.put("name", "ceshi");
        map.put("password", "123456");
        System.out.println(map.toString()); //{password=123456, name=ceshi}
        System.out.println(JSON.toJSONString(map)); //{"name":"ceshi","password":"123456"}

        JSONObject json = new JSONObject();
        json.put("name", "ceshi");
        json.put("password", "123456");
        System.out.println(json.toJSONString()); //{"name":"ceshi","password":"123456"}
    }

 

posted on 2019-04-15 20:09  木风向前冲  阅读(4810)  评论(0编辑  收藏  举报