如何在程序中获取Oracle服务名

 

 1。查询注册表，获取oracle安装根目录
           HKEY_LOCAL_MACHINE\SOFTWARE\ORACLE\ORACLE_HOME   REG_SZ  E:\ORACLE\ORA92
            得知oracle服务名文件所在地：根目录\network\ADMIN\tnsnames.ora
            
 

2。解析该文件，该文件结构如
            # ------------------------------------------------
            PORTAL =
            (DESCRIPTION =
                (ADDRESS_LIST =
                (ADDRESS = (PROTOCOL = TCP)(HOST = 134.104.52.6)(PORT = 1521))
                )
                (CONNECT_DATA =
                (SERVICE_NAME = portal)
                )
            )

3。解析要点：
            一行一行获取再解析
            跳过以#打头的注释行
            过滤掉空格后，首字符在A~z之间的行就包含了Oracle服务名
            截取该行第一个“＝”号左边的字符串，trim处理后就是Oracle服务名了  

private string[]  TnsNameRead()
        {
            ArrayList arr = new ArrayList();
            string path = (string)Registry.LocalMachine.OpenSubKey("SOFTWARE\\ORACLE").GetValue("ORACLE_HOME");
            path += @"\network\admin\tnsnames.ora";
            try 
            {
                using (StreamReader sr = new StreamReader(path)) 
                {
                    String line;
                    while ((line = sr.ReadLine()) != null) 
                    {
                        line = line.Trim();
                        if (line != "")
                        {
                            char c = line[0];
                            if ( c>= 'A' && c<='z')
                            {
                                arr.Add(line.Substring(0, line.IndexOf('=')).Trim());
                                MessageBox.Show(line.Substring(0, line.IndexOf('=')).Trim());
                            }
                        }
                    }
                }
            }
            catch (Exception e) 
            {
                MessageBox.Show("无法打开tnsnames.ora文件\n"+ e.Message , "警告", MessageBoxButtons.OK, MessageBoxIcon.Stop);
            }
            return (string[])arr.ToArray(typeof(string));
        }